An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The system's potential energy when kinetic energy of (3/4) E is (1/8) k A².
<h3>What is mechanical energy?</h3>
Mechanical energy is the sum of potential energy and kinetic energy.
Total mechanical energy = P.E max = K.E max
Total mechanical energy = K.E +P.E
Given is the kinetic energy is (3/4)E.
E= (3/4)E + P.E
P.E = (1/4) E
Maximum potential energy =E = (1/2) k A²
Here. A is the maximum displacement and k is the spring constant.
The potential energy at kinetic energy of (3/4) E is
P.E = (1/4)E = (1/8) k A²
Therefore, the system's potential energy when kinetic energy of (3/4) E is (1/8) k A².
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Answer:
a) 0.00996 m
b) 109090909 Pa
Explanation:
Unit conversions:
1.2 mm = 0.0012 m
8.5 kN = 8500 N
If the 2.2m rod cannot stretch more than 0.0012 m, its maximum strain is
With elastic modulus being E = 200 GPa, then its maximum stress must be
Knowing the tension force being F = 8500 N, we can calculate the appropriate cross section area
And its corresponding diameter is
Answer:
Explanation:
Scientist use many techniques to analyze and interpret data. To interpret data they make tables and graphs of data which are two of the most useful techniques in data analysis.
It will be
E = mgh.
where h and g are constant thus
m can be written as 4/3πr^3*density
E = 4/3πr^3* density
E? = 4/3π(2R)^3* density
= 4/3π8r^3
thus the e will be 4/3π8r^3* density/4/3πr^3*density nd thus you get 8E ..
