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iris [78.8K]
3 years ago
12

Brad walks and jogs to schooll every day. He averages 5 km/hr walking and 9 km/hr jogging. The distane from home to shool is 6 k

m, and the total trip takes 1 hour. How far does Brad walk?
Physics
1 answer:
Vitek1552 [10]3 years ago
5 0
We know that
Distance = speed x time
Let w be the time Brad spent walking. The time spent jogging will be 1 - w
6 = 5w + 9(1 - w)
w = 0.75 hours
Distance walked = 0.75 x 5
= 3.75 km
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The Olympic record for running the 200 m dash is 19.3 seconds. What is the average speed for this record?
Hoochie [10]

Answer:

A

Explanation:

v = change of X / change of T

v = 200/19.3

8 0
3 years ago
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A motor with an operating resistance of 32 ohms is connected to a voltage source. the current in the circuit is 3.8
Phantasy [73]

V = I · R = (3.8 Amperes) · (32 ohms) = 121.6 volts
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3 years ago
A parachutist weighs 1000N. when she opens her parachute, it pulls upwards on her with a force of 2000N. (a) draw a diagram to s
Nataly_w [17]

(a) Find free-body diagram in attachment (please rotate the picture, such that R points upward and mg points downward)

There are only two forces acting on the parachutist:

- Its weight, downward, of magnitude 1000 N, labelled with "mg" in the diagram (where m = mass of the parachutist, g = acceleration of gravity)

- The air resistance, upward, of magnitude 2000 N, labelled with "R" in the diagram

As the air resistance is larger than the weight, in the diagram it is represented with a longer arrow, in order to show the difference in magnitude.

(b) 1000 N, upward

By taking upward as positive direction, we can rewrite the two forces as:

R = +2000 N

mg = -1000 N

Where we have written the weight as a negative number, since its direction is downward.

Therefore, the net force on the parachutist will be

F = R + mg = +2000 + (-1000) = +1000 N

And the positive sign indicates that the resultant force is upward.

(c) The parachutist will be accelerated upward (= he/she will slow down)

We can answer this part by applying Newton's second law, which is summarized by the following:

F=ma (1)

where

F is the resultant force on the body

m is its mass

a is its acceleration

For the parachutist in this problem, the mass is

m=\frac{mg}{g}=\frac{1000 N}{9.8 N/kg}=102 kg

Therefore, using (1), we find the acceleration of the parachutist:

a=\frac{F}{m}=\frac{+1000}{102}=+9.8 m/s^2

Where the positive sign indicates that the acceleration is upward. Therefore, the parachutist will be accelerated upward, which means that he/she will slow down, since its direction of motion was downward.

4 0
3 years ago
A horizontal air diffuser operates with inlet velocity and specific enthalpy of 250 m/s and 270.11 kj/kg, repectively, and exit
Ivahew [28]

Answer: c) 90 m/s

Explanation:

Given

Invest velocity, v1 = 250 m/s

Inlet specific enthalpy, h1 = 270.11 kJ/kg = 270110 J/kg

Outlet specific enthalpy, h2 = 297.31 kJ/kg = 297310 J/kg

Outlet velocity, v2 = ?

0 = Q(cv) - W(cv) + m[(h1 - h2) + 1/2(v1² - v2²) + g(z1 - z2)]

0 = Q(cv) + m[(h1 - h2) + 1/2(v1² - v2²)]

0 = [(h1 - h2) + 1/2(v1² - v2²)]

Substituting the values of the above, we get

0 = [(270110 - 297310) + 1/2 ( 250² - v²)

0 = [-27200 + 1/2 (62500 - v²)]

27200 = 1/2 (62500 - v²)

54400 = 62500 - v²

v² = 62500 - 54400

v² = 8100

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4 0
3 years ago
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vazorg [7]

Answer:

Instantaneous velocity at the red light is 0 m/s.

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Explanation:

Instantaneous velocity is the velocity of a body at any given moment of time.

It's the current speed and direction in which it acts.

When the bus is at the red light, it is not in motion at that point. So, the instantaneous velocity of the bus is 0 m/s at that moment of time.

Again, at another point, the bus is moving with constant speed of 18 m/s, so the instantaneous velocity is also 18 m/s but with a specified direction as velocity is a vector quantity.

So, the instantaneous velocity when the bus is moving with constant speed is 18 m/s towards north.

3 0
3 years ago
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