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3 years ago

HELP ASAP!!!!!!!!! What is the difference between a contact force and a distance force?

2 answers:

6 0

A contact force are forces that require actual contact (touch) of two pieces of matter.

Distant force is a force that works at a distance not needing any contact (touch) at all.

jek_recluse [69]3 years ago

5 0

Think contact requires contact (touch) and distance requires distance (no touch)

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Under what condition will a glass lens placed in a transparent medium becomes invisible??

Viktor [21]

Answer:

A lens placed in a transparent liquid becomes invisible because when refractive index of the material of the lens is equal to the refractive index of the liquid in which lens is placed under this condition no bending of light takes place when it travels from liquid to the lens, so both will start behaving like both are same things.

Explanation:

hope it helps :))

5 0

3 years ago

An egg, which can be assumed to b a 5-cm diameter sphere having the thermal properties of water, is initially at a temperature o

dolphi86 [110]

Answer:

The temperature is 90.4°C

Explanation:

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6 0

3 years ago

Which of the following is the tendency of an object to maintain its state of

densk [106]

Answer:

O inertia

Explanation:

The tendency of a body to maintain its state of motion is inertia.

Inertia is the tendency of a body to remain at rest or in constant motion.

According to newtons first law of motion "a body will remain in its state of rest or constant motion unless acted upon by an external force".
The tendency of the body to remain in a state of rest or of constant motion is the inertia.
Such a body will not want to accelerate or change motion.

7 0

3 years ago

A cricket ball is dropped from a height of 20 m. Calculate: a) the speed of the ball. b) the time it takes to fall through this

AysviL [449]

Answer:

Initial velocity is 0 .. ( since it is just dropped)

now using V²= u² +2gh

=> (Vfinal)² = 0+2*10*20

=> v² = 20*20 = 400

=> v = √400 = 20m/s

for time taken

use V = u+gt

=> t = V/g = 20/10 = 2sec

7 0

2 years ago

An object moves in a straight path. Its position x as a function of time t is presented by the equation x(t) = at – bt2+c, where

ankoles [38]

Answer:

The answer is below

Explanation:

Given that:

x(t) = at – bt2+c

a) x(t) = at – bt2+c

Substituting a = 1.4 m/s, b = 0.06 m/s2 and c =50 m gives:

x(t) = 1.4t - 0.06t² + 50

At t = 5, x(5) = 1.4(5) - 0.06(5)² + 50 = 55.5 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

$v=\frac{x(5)-x(0)}{5-0}\\ \\v=\frac{55.5-50}{5-0}=1.1\\ \\v=1.1\ m/s$

b) x(t) = 1.4t - 0.06t² + 50

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

$v=\frac{x(10)-x(0)}{10-0}\\ \\v=\frac{58-50}{10-0}=0.8\\ \\v=0.8\ m/s$

c) x(t) = 1.4t - 0.06t² + 50

At t = 15, x(5) = 1.4(15) - 0.06(15)² + 50 = 57.5 m

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

The average velocity (v) is given as:

$v=\frac{x(15)-x(10)}{15-10}\\ \\v=\frac{57.5-58}{15-10}=0.1\\ \\v=0.1\ m/s$

6 0

3 years ago