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2 years ago

1: In a longitudinal wave, the particle displacement is __________ the direction of wave movement

Physics

1 answer:

jenyasd209 [6]2 years ago

5 0

The answer is parallel

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Playing near a road construction site, a child falls over a barrier and down onto a dirt slope that is angled downward at 33° to

Debora [2.8K]

Answer:

$\mu_{k} \approx 0.719$

Explanation:

The equations of equilibrium for the child are: (x' in the direction parallel to slope, y' in the direction perpendicular to slope)

$\Sigma F_{x'} = m\cdot g \cdot \sin \theta - \mu_{k}\cdot N = m\cdot a\\\Sigma F_{y'} = N - m\cdot g\cdot \cos \theta = 0$

After some algebraic manipulation, an expression for the coefficient of kinetic friction is obtained:

$m\cdot g\cdot \sin \theta - \mu_{k}\cdot m \cdot g \cos \theta = m \cdot a$

$g \cdot (\sin \theta - \mu_{k}\cdot \cos \theta) = a$

$\mu_{k}\cdot \cos \theta = \sin \theta - \frac{a}{g}$

$\mu_{k} = \frac{1}{\cos \theta}\cdot (\sin \theta - \frac{a}{g} )$

$\mu_{k} = \frac{1}{\cos 33^{\textdegree}}\cdot \left(\sin 33^{\textdegree}-\frac{(-0.57\,\frac{m}{s^{2}}) }{9.807\,\frac{m}{s^{2}} } \right)$

$\mu_{k} \approx 0.719$

5 0

3 years ago

A sound source producing 1.00 kHz waves moves toward a stationary listener at one-half the speed of sound.

SIZIF [17.4K]

Answer:

2000Hz and 1500Hz

Explanation:

Using

a) f = f0((c+vr)/(c+vs))

=>>> f0((c)/(c-0.5c))

=>>>1000/0.5 = 2000Hz

b) f = f0((c+vr)/(c+vs))

=>>>f0((c+0.5c)/(c))

=>>>>1000 x 1.5 = 1500Hz

5 0

3 years ago

URGENT BY THE WAY!

Nastasia [14]

Answer:

So Nessa went so fast it made her pass the tile in a second. Lets take a look at this problem, It says "the" tile so we should assume that it means 1 tile. Then draw a diagram representing that tile then you should have your problem finished. Hope that helped and I'm willing to help if you have anymore questions!

Explanation:

6 0

2 years ago

Turning a corner at a typical large intersection in a city means driving your car through a circular arc with a radius of about

Naddik [55]

Answer:

9.89 m/s.

Explanation:

Given that,

The radius of the circular arc, r = 25 m

The acceleration of the vehicle is 0.40 times the free-fall acceleration i.e.,a = 0.4(9.8) = 3.92 m/s²

Let v is the maximum speed at which you should drive through this turn. It can be solved as follows :

$a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{3.92\times 25} \\\\=9.89 m/s$

So, the maximum speed of the car should be 9.89 m/s.

8 0

2 years ago

Please help! Science and force stuff. (picture included)

Nikitich [7]

#4. It says "someone sitting in a chair" So the objects involved are the person and the chair. D is the answer because it talks about the action/reaction forces between the person and the chair.

#5. Work = Force (parallel to direction of distance) * distance. A, B and D are not correct because there is no distance. C. is the best answer

4 0

3 years ago