5-32
10-64
15-96
1 more to make 16. 5 divided into 32 equals 5.7
Total 101.7
The length of a diagonal of a square is the side*sqrt(2). Let's call one side of the square: s
So we have 18 = s*sqrt(2)
18/sqrt(2) = s
18sqrt(2)/2 = s
9sqrt(2) = s
Since the perimeter is 4 sides we multiply by 4 to get 36sqrt(2) as the perimeter.
First step is breaking down the word problem.
I think of a number.
U don’t know the number so called it x
The number add 3.
X + 3
Then it says multiply the outcome by 7
You are not sure what what the outcome could be so you put it in brackets
(X+3) times it by 7
(X+3) 7
The solution is 24.5
Solution means equal
(X+3) 7 = 24.5
Now you have the equation
To solve for x
By the BOMDAS method
You times 7 by what is inside the brackets
7x + 21 = 24.5
Now transpose
7x = 24.5 - 21
7x = 3.5
Divide both sides by 7
7x/7 = 3.5/7
Which cancel out 7 and leave x
So the original number is
Or u could say x = 0.5
Answer: f(x)= 8
Step-by-step explanation:
First you would plug in F(3) into the equation
replace the x with a three
f(x)=2(3)+2
then multiply the 2 and 3 because when you see a number next to another number in parenthesis you multiply them
f(x)=6+2
Then lastly you would add the result of your multiplied numbers with the two which gives you f(x)=8.
<u>f(x)=8</u>
The value of the algebraic expressions when x = 5 are:
a) x² = <em>25</em>
<em>b) </em>(x + 3)² = <em>64</em>
We are given that x = 5.
<em>Required:</em>
Find the value of a.) x² and b.) (x + 3)²
To find the value of each algebraic expression when x = 5, substitute the value of x.
<em>Thus:</em>
a.) x²
x² = (5)²
x² = <em>25</em>
<em />
b.) (x + 3)²
(x + 3)² = (5 + 3)²
(x + 3)² = (8)²
(x + 3)² = <em>64</em>
Therefore, the value of the algebraic expressions when x = 5 are:
a) x² = <em>25</em>
<em>b) </em>(x + 3)² = <em>64</em>
Learn more about algebraic expressions on:
brainly.com/question/90420