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4 years ago

Complete and balance the equation for this reaction in acidic solution. zns+no3-

1 answer:

8 0

The equation given in question is as follow,

   ZnS + NO₃⁻   → Zn²⁺ + S + NO

Oxidation state of elements in reactant side are as follow,
Zn = +2
S = -2
N = +5
O = -2
Oxidation state of elements in product side are as follow,
Zn = +2
S = 0
N = +2
O = -2
So, In this reaction Nitrogen is Reduced while Sulfur is Oxidized.

Now Split the reaction into two half cell reactions,

Reduction Reaction,
ZnS → S + 2e⁻
Oxidation Reaction,
NO₃⁻ + 3e⁻   → NO

As the oxygen atoms are not balance, So, in acidic medium add H⁺ on the side having greater number of Oxygen atom and H₂O on the side having less number of Oxygen atoms,
Hence,
H⁺ + NO₃⁻ + 3e⁻    → NO + H₂O
Now Balance the reaction,

4H⁺ + NO₃⁻ + 3e⁻    → NO + 2H₂O

So, write both half cell equations as,

ZnS → S + 2e⁻ --------- (1)
4H⁺ + NO₃⁻ + 3e⁻    → NO + 2H₂O -------(2)

Multiply eq. 1 with 3 and eq. 2 with 2 to equalize the electron.
So,
3ZnS → 3S + 6e⁻

8H⁺ + 2NO₃⁻ + 6e⁻    → 2NO + 4H₂O
_____________________________________(e⁻ cancelled)

3ZnS + 2NO₃⁻ + 8H⁺ → 3Zn + 3S + 2NO + 4H₂O

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3 years ago

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Which of the following conditions explains Floridas risk of muck fires

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3 years ago

A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at

weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of tin = $m_1=18.5 g$

Specific heat capacity of tin = $c_1=0.21 J/g^oC$

Initial temperature of the tin = $T_1=97.38^oC$

Final temperature = $T_2$ =T

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2=75.7 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=21.52^oC$

Final temperature of water = $T_2$ =T

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

$-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)$

we get, T = 22.44°C

22.44°C will be the final temperature of the water.

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4 years ago

Which of the following would have a fixed shape and volume?

Masja [62]

Answer is: solid wood.

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In solid, molecules are closely packed, stiff and do not changes of shape or volume. Solid object (in this example wood) does not take on the shape of its container.
Liquids (in this example water) have definite volume, but no fixed shape.
Gases (in this example nitrogen and neeon) not have definite volume and fixed shape, it depends on its container.

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4 years ago