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aksik [14]
3 years ago
5

What is the frequency of the sinusoidal graph?

Chemistry
1 answer:
Arisa [49]3 years ago
8 0

Answer:

For finding frequency, we need to first find the period of the graph.

The period of a sinusoidal graph is the time interval in which it repeats its pattern.

In the graph, we can see, after 1/period time, it repeats its pattern.

Hence the period of the graph is  \pi /2.

Now we need to find its frequency 1/\pi /2

The formula for frequency is 2/\pi

This is the answer

i hope you pass the assignment

try your best!

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Arrange the following compounds in order of DECREASING boiling points (going from the highest to the lowest):
Gennadij [26K]

Answer:

b

d

a

c

Explanation:

More carbons in longest chain = higher BP

D has a BP of 0.8

A has a BP -0.5

C is the lowest because the more branched it is the lower BP

6 0
3 years ago
Determine which of the following contains the greatest mass of aluminium: 122 g of AlPO4, 266 g of A12C16, or 225 g of
pav-90 [236]

Answer : The Al_2S_3 contains the greatest mass of aluminum.

Explanation :

<u>For AlPO_4 :</u>

Molar mass of AlPO_4 = 122 g/mole

Molar mass of aluminium = 27 g/mole

As, 122 g of AlPO_4 contains 27 g of Al

So, 122 g of AlPO_4 contains \frac{122}{122}\times 27=27g of Al

The mass of 'Al' in AlPO_4 is, 27 grams.

<u>For Al_2Cl_6 :</u>

Molar mass of Al_2Cl_6 = 266.7 g/mole

Molar mass of aluminium = 27 g/mole

As, 266.7 g of Al_2Cl_6 contains 2\times 27g of Al

So, 266 g of Al_2Cl_6 contains \frac{266}{266.7}\times 2\times 27=54g of Al

The mass of 'Al' in Al_2Cl_6 is, 54 grams.

<u>For Al_2S_3 :</u>

Molar mass of Al_2S_3 = 150 g/mole

Molar mass of aluminium = 27 g/mole

As, 150 g of Al_2S_3 contains 2\times 27g of Al

So, 225 g of Al_2S_3 contains \frac{225}{150}\times 2\times 27=81g of Al

The mass of 'Al' in Al_2S_3 is, 81 grams.

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5 0
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How did you figure out the number of neutrons in each atom?
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To get number of neutrons, you must have the mass number and atomic number of that atom.

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8 0
3 years ago
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From equation;
P1V1=P2V2
V2=P1V1÷P2
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now;1atm=760mmHg
how about 380mmHg is equal to how many atm?
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P2 now is equal to 0.5atm
back from equation;
P1V1=P2V2
V2=P1V1÷P2
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