Is there any more detail you can add for this ?
Answer: im not sure im only in 8th grade but im pretty sure Erosion i started learning about this last year i really cant explain it... im still hainving trouble with it.
Explanation:
<u>Answer:</u> 1.461 g of NaCl is dissolved in the solution.
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.
The formula used to calculate molarity:
.....(1)
Given values:
Molarity of solution = 0.050 M
Molar mass of NaCl = 58.44 g/mol
Volume of solution = 500.0 mL
Putting values in equation 1, we get:
Hence, 1.461 g of NaCl is dissolved in the solution.
Answer:
1.1 × 10⁻⁶ M
Explanation:
Step 1: Given and required data
- Concentration of Ca²⁺ ([Ca²⁺]): 2.5 mM = 2.5 × 10⁻³ M
- Calcium oxalate solubility product constant (Ksp): 2.7 × 10⁻⁹
Step 2: Write the balanced equation for the solution reaction of calcium oxalate
CaC₂O₄(s) ⇄ Ca²⁺(aq) + C₂O₄²⁻(aq)
Step 3: Calculate the concentration of the oxalate ion to begin the precipitation of calcium oxalate
We will use the Ksp of calcium oxalate.
Ksp = 2.7 × 10⁻⁹ = [Ca²⁺].[C₂O₄²⁻]
[C₂O₄²⁻] = Ksp / [Ca²⁺]
[C₂O₄²⁻] = 2.7 × 10⁻⁹ / 2.5 × 10⁻³
[C₂O₄²⁻] = 1.1 × 10⁻⁶ M
Answer:
Explanation:
no. of moles of butane = 5.87g / 58.124 = 0.1009mol
since O2 is excess, limiting reagent is butane
from the equation, 2 moles of butane will reacted to produce water = 10 moles
therefore, 0.1009 moles of butane produced water = (0.1009 x 5) = 0.5050 moles
Weight of H2O formed = 0.5050 x 18.015 = 9.10 grams
