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goldenfox [79]
1 year ago
12

Suppose that $3$ is a factor of $a$, $a$ is a divisor of $12$, and $a$ is positive. What is the number of possible values of $a$

Mathematics
1 answer:
antiseptic1488 [7]1 year ago
8 0

If a is a divisor of 12, then

a \in \{-12, -6, -4, -3, -2, -1, 1, 2, 3, 4, 6, 12\}

If 3 is a factor (i.e. divisor) of a, then a can only be one of the elements of this set that are multiples of 3, so

a \in \{-12, -6, -3, 3, 6, 12\}

But a is positive, so there are 3 possible values a can have.

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