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Gwar [14]
3 years ago
15

Picture of the question is below, if answered correctly, I will reward with brainliest.

Chemistry
1 answer:
BARSIC [14]3 years ago
6 0

Answer:

1. Number 3

2. Number 1

3. Number 5

4. Number 4

5. Number 2

I think, this is the order.

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All + HgCl, --------> AICI,
Free_Kalibri [48]

Answer:

64.7g

Explanation:

The balanced chemical equation of this question is as follows;

AlI + HgCl2 → HgI + AlCl2

Based on the above equation, 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide).

Using mole = mass/molar mass to convert mass of HgI to moles.

Molar mass of HgI = 200.59 + 127

= 327.59g/mol

Mole = 138/327.59

= 0.42mol

- If 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide)

- Then 0.42 mol of HgI will be produced by 0.42mol of AlI.

Using mole = mass/molar mass

Mass = mole × molar mass

Molar mass of AlI = 27 + 127

= 154g/mol

Mass of AlI = 0.42 × 154

= 64.7g of AlI

5 0
3 years ago
Plz help guys ASAP! <br> Thanks in advance
MariettaO [177]

Answer:

3.6 moles

Explanation:

The balanced equation for the reaction is given below:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

1 mole of N₂ reacted with 3 moles of H₂ to produce 2 moles NH₃.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N₂ reacted with 3 moles of H₂.

Therefore, 3.2 moles of N₂ will react with = 3.2 × 3 = 9.6 moles of H₂.

From the calculation made above, we can see that it will take a higher amount (i.e 9.6 moles) of H₂ than what was given (i.e 5.4 moles) to react completely with 3.2 moles of N₂.

Therefore, H₂ is the limiting reactant and N₂ is the excess reactant.

Finally, we the greatest quantity of ammonia, NH₃ produced from the reaction.

In this case, the limiting reactant will be use because all of it is consumed in the reaction.

The limiting reactant is H₂ and greatest quantity of ammonia, NH₃ produced can be obtained as follow:

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

Therefore, 5.4 of H₂ will react to produce = (5.4 × 2)/3 = 3.6 moles of NH₃

Thus, the greatest quantity of ammonia, NH₃ produced from the reaction is 3.6 moles

4 0
3 years ago
A 17.9 mL sample of a 0.445 M aqueous hypochlorous acid solution is titrated with a 0.374 M aqueous sodium hydroxide solution. W
In-s [12.5K]

Answer:

the pH at the start of the titration is 3

4 0
3 years ago
What is the answers?
ra1l [238]

the numbers are going to be small so like a power but its at the bottom

NH3, H2O2, NHO2

5 0
3 years ago
What group of elements generally have the lowest second ionization energy?
ICE Princess25 [194]
<span>By definition, the first ionization energy is the energy required to remove the most loosely held electron from one mole of gaseous atoms to produce 1 mole of gaseous ions each with a charge of 1+. </span><span />
4 0
3 years ago
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