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2 years ago

Consider the oxidation of sodium metal to sodium oxide described by the balanced equation:

Chemistry

1 answer:

mixas84 [53]2 years ago

3 0

Answer:

1116 g.

Explanation:

The balanced equation for the reaction is given below:

4Na + O₂ —> 2Na₂O

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of Na₂O.

Next, we shall determine the theoretical yield of Na₂O. This can be obtained as follow:

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of Na₂O.

Therefore, 9 moles of O₂ will react to produce = 9 × 2 = 18 moles of Na₂O.

Finally, we shall determine the mass in 18 moles of Na₂O. This can be obtained as follow:

Mole of Na₂O = 18 moles

Molar mass of Na₂O = (23×2) + 16

= 46 + 16

= 62 g/mol

Mass of Na₂O =?

Mass = mole × molar mass

Mass of Na₂O = 18 × 62

Mass of Na₂O = 1116 g

Thus, the theoretical yield of Na₂O is 1116 g.

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Binary compounds of alkali metals and hydrogen react with water to liberate hydrogen gas. The hydrogen gas from the reaction of

DanielleElmas [232]

Answer: The mass of $H_{2}$ liberated is 0.0383 g and the mass of NaH that reacted 0.455 g.

Explanation:

The given data is as follows.

Volume = 0.501 L,

Temperature of gas = $35^{o}C$ = (35 + 273) K = 308 K,

Total pressure = 760 mm Hg

Vapor pressure of water at $35^{o}C$ = 422 mm Hg

Partial pressure of $H_{2}$ = (760 - 422) mm Hg

= 717.8 mm Hg

The chemical equation is as follows.

$NaH + H_{2}O \rightarrow NaOH + H_{2}$

Using ideal gas equation, we will find the moles of hydrogen gas as follows.

PV = nRT

n = $\frac{PV}{RT}$

As we know,

1 atm = 760 mm Hg

717.8 mm Hg = $717.8 \times \frac{1 atm}{760 mm Hg}$

= 0.944 atm

Putting the given values into the above formula we will calculate the number of moles as follows.

n = $\frac{PV}{RT}$

= $\frac{0.944 atm \times 0.510 L}{0.08206 Latm/mol K \times 308 K}$

= 0.0190 moles

Now, we will find the mass of $H_{2}$ as follows.

Mass = Moles × Molar mass

= 0.0190 moles × 2.01588 g/mol

= 0.0383 g

Therefore, mass of hydrogen is 0.0383 g.

As the ratio between $H_{2}$ and NaH is 1:1. So, we will calculate the moles of NaH as follows.

Mass = Moles × Molar mass

= 0.0190 moles × 23.99771 g/mol

= 0.455 g

Therefore, mass of NaH is 0.455 g.

6 0

3 years ago

........PLEASE HELP........

murzikaleks [220]

You can look your question up in the Brainly ask your question. It’s in there!

5 0

3 years ago

What is m/e ratio???????????

Roman55 [17]

Answer: Hello,Mass ratio charge is.....................

Explanation: In mass spectroscopy, the mass-to-charge ratio (symbols: m/z, m/e) of a cation is equal to the mass of the cation divided by its charge. ... The mass of the molecular ion is equal to the molecular weight of the compound. Thus, the mass-to-charge ratio of the molecular ion is equal to the molecular weight of the compound.

8 0

2 years ago

Classify the following changes as physical or chemical changes. a. Water boils. b. Salt dissolves in water c. Milk turns sour d.

geniusboy [140]

Answer:

Water boils - physical change

Salt dissolves in water- chemical change

Milk turns sour- chemical change

metal rusts - chemical change

Explanation:

A chemical change refers to changes that are irreversible and the process involves the evolution of heat along with the formation of a new substance, examples include;Salt dissolves in water, Milk turns sour, metal rusts etc

The boiling of water is a physical change. The water can be cooled and the vapour condensed,hence, the boiling of water is a physical change.

Physical changes are easily reversible and no new substance is formed.

6 0

3 years ago

Please answer this question!

Hunter-Best [27]

1,2-dimbromopropane would be something like C which is the second best answer.

B would be correct if it had another carbon.

A is like C but incorrect for the same reason. 1,2-dibromoethane is what A is.

The answer has to be D where the bromines are right across from each other.

3 0

3 years ago