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luda_lava [24]
3 years ago
15

How much Oxygen would be required to react with 101 g of Methane?

Chemistry
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

404g

Explanation:

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In general ethers have a much lower boiling point than their isomeric alcohols. why?
Alex Ar [27]

Ethers have a much lower boiling point than their isomeric alcohols because ether have not hydrogen bond that why ethers have lower boiling point .

Ethers will not have a hydrogen atom attached to the oxygen atom as alcohols do. Because ether molecules can not form intermolecular hydrogen bonds, their boiling points are much shorter than those of alcohol with such a comparable mass.

Owing to the combination of intermolecular H-bonding in alcohols though not in ethers, alcohols possess higher boiling temperatures than isomeric ethers.

Therefore, ethers have a much lower boiling point than their isomeric alcohols because ether have not hydrogen bond that why ethers have lower boiling point .

To know more about boiling point

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4 0
1 year ago
Calculate number of particles in 46 g of Na atoms
Harman [31]
The number of particles in 46g of Sodium (Na) atoms are 2.00088735004 mol 
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3 years ago
Engineers often attempt to capture and reuse energy or to use renewable resources to minimize harm to the environment. This is r
leva [86]
THIS IS KNOW AS A GREEN DESIGN 
5 0
3 years ago
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Find the mass of 11.37 mol of BaO. Round to the nearest whole number. *
viva [34]
1740 g because the molar mass is 133.33g/mol, mulitplied by 11.37 mol = 1743.36. 1740 is closest and it may be a bit off depending on how many sig figs are used for the molar mass. So 1740g
6 0
3 years ago
Student weighs out 0.287 g of ascorbic acid (H2CH06), a diprotic acid, into a 250. mL k and dilutes to the mark with distilled w
pav-90 [236]

Explanation:

It is given that mass of ascorbic acid = 0.287 g

As molar mass of ascorbic acid is 176.12 g/mol. Hence, calculate its number of moles as follows.

moles ascorbic acid = \frac{\text{mass ascorbic acid}}{\text{molar mass ascorbic acid}}

           moles ascorbic acid = \frac{0.287 g}{176.12 g/mol}

                                             = 1.63 \times 10^{-3} mol

So, moles of H^{+} = 2 \times \text{(moles ascorbic acid)}

                                 = 2 \times (1.63 \times 10^{-3} mol)

                                 = 3.26 \times 10^{-3} mol

Therefore, moles NaOH required = moles H^{+}

     moles NaOH required = 3.26 \times 10^{-3} mol

Now, we will calculate the volume of NaOH as follows.

          volume NaOH = \frac{\text{moles NaOH required}}{\text{molarity NaOH}}

            volume NaOH = \frac{3.26 \times 10^{-3} mol}{0.0500 M)}

                                    = 0.0652 L

or,                                = 65.2 mL              (as 1 L = 1000 ml)

Thus, we can conclude that the volume of NaOH required is 65.2 ml.

7 0
3 years ago
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