Explanation:
here's the molecule you were looking for
The theoretical yield of I2 in the reaction would be 0.23 g
<h3>Theoretical yield</h3>
This refers to the stoichiometric yield of a reaction.
From the equation of the reaction:
Ca(IO3)2 + 10 KI + 12 HCl → 6 I2 + CaCl2 + 10 KCl + 6 H2O
The mole ratio of Ca(IO3)2 and I2 is 1: 6
Mole of 15.00 mL, 0.0100 M Ca(IO3)2 = 15/1000 x 0.0100
= 0.00015 mole
Equivalent mole of I2 = 0.00015 x 6
= 0.009 mole
mass of 0.0009 I2 = 0.0009 x 253.809
= 0.23 g
More on stoichiometric calculations can be found here: brainly.com/question/6907332
Answer:
32÷5
I'm just tryna get points I'm sorry
goodluck tho❤
Chlorine, Anthax is a biological agent, and uranium is a radioactive agent, and dynamite is just a no. Chlorine is a chemical gas.
The key to most "how do I separate." questions is solubility.
The trick is to add a liquid that will only dissolve one substance but not another.
Let's say you had a beaker full of sand, table salt (NaCl), and acetanilide. Is there anything you can add that would only dissolve one of these three substances?
Yes, there is! Acetanilide like most organic compounds, isn't soluble in water. But salt is soluble in water. So to the mixture, I would add water, and then pass the water through a filter. The filter paper will "catch" the sand and acetanilide, but the table salt will remain dissolved in the water. If you then let that water evaporate (either via boiling or under vacuum), you will recover your salt.
So now, how to do you separate the sand from the acetanilide? Sand isn't really soluble in anything, but acetanilide is soluble in organic solvents, such as ethanol. So to the mixture of sand and acetanilide, add ethanol, and pass it through a filter. The sand will once again get stuck in the filter paper, and your acetanilide will be dissolved in ethanol. Remove the ethanol (via vacuum, or rotovap) and you will be left with acetanilide.
