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3 years ago

Which is the largest group of mollusks?

Chemistry

2 answers:

KonstantinChe [14]3 years ago

3 0

Answer:

Gastropoda.

Explanation:

Sliva [168]3 years ago

3 0

Answer:

The correct answer is D. Gastropods.

Explanation:

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Quarks are A A Fact B Fiction C Both of the above D Neither of the above

stiks02 [169]

I’d say A. They are theoretical in the fact that they have not been observed directly, but have been confirmed to exist through experimentation.

7 0

2 years ago

What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm

Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

Difference in mass = 985.32 - 984.5 = 0.82 g

Explanation:

Part I :

$n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}$

n = 4.9983

n = 4.99 moles

(Note : You can also take n = 5 mole )

Molar mass of gold = 196.96 g/mole

This means, 1 mole of gold(Au) contain = 196.96 grams

So, 4.99 moles of gold contain = $5\times 196.96$ g

4.99 moles of gold contain = 984.8 g

Mass of ${3.01\times 10^{24}}$ atoms of gold = 984.5 g

Part II :

Density of Gold = $19.32 g/cm^{3}$

Volume of the cuboid = $length\times breadth\times height$

Volume of the gold bar = $6.00\times 4.25\times 2.00$

Volume of the gold bar = 51 $cm^{3}$

Using formula,

$Density = \frac{mass}{Volume}$

$Mass = Density\times Volume$

$Mass = 19.32 \times 51$

Mass = 985.32 g

So, A gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of 985.32 g

Difference in mass = 985.32 - 984.5 = 0.82 g

3 0

3 years ago

Which best describes the data?

blondinia [14]

Answer:

The average?

Explanation:

8 0

3 years ago

Which of the following ions is formed when the positive hydrogen ions from an acid bond to water molecules? он- ООН- он20* ОНО*

Vesna [10]

Answer:

2ND ONE

Explanation:

5 0

2 years ago

How many atoms of mercury are present in 3.2 cubic centimeters of liquid mercury? the density of mercury is 13.55 g/cc. answer i

jenyasd209 [6]

Answer:

1.3 × 10²³ Atoms of Mercury

Solution:

Step 1: Calculate Mass of Mercury using following formula,

Density = Mass ÷ Volume

Solving for Mass,

Mass = Density × Volume

Putting values,

Mass = 13.55 g.cm⁻³ × 3.2 cm³ ∴ 1 cm³ = 1 cc

Mass = 43.36 g

Step 2: Calculating number of Moles using following formula;

Moles = Mass ÷ M.mass

Putting values,

Moles = 43.36 g ÷ 200.59 g.mol⁻¹

Moles = 0.216 mol

Step 3: Calculating Number of Atoms using following formula;

Number of atoms = Moles × 6.022 ×10²³

Putting value of moles,

Number of Atoms = 0.216 mol × 6.022 × 10²³

Number of Atoms = 1.3 × 10²³ Atoms of Hg

7 0

3 years ago