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umka2103 [35]
3 years ago
11

In order to do multiple trials of an experiment, _____. A. change your hypothesis B. do the experiment more than once C. revise

your procedure to make it better D. try the experiment using different chemicals
Chemistry
1 answer:
Arisa [49]3 years ago
8 0

B. do the experiment more than once

Explanation:

To do a multiple trials of an experiment, it is best to do the experiment more than once.

Experimental trials are mere replication of the procedures in an experiment.

  • Most hypothesis on which experiments are based must be repeatable.
  • When experiments are repeated through several trials, their accuracy is increased.
  • Multiple trials clearly makes it easy to make meaningful deductions from an experimental process.

Learn more:

Experiment brainly.com/question/5096428

#learnwithBrainly

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List two non-metal elements that combine with three hydrogen atoms to satisfy the octet rule
viva [34]
  • Nitrogen as in NH₃.
  • Phosphorous as in PH₃.
<h3>Explanation</h3>

Hydrogen is in group 1. It is one electron away from the next noble gas element. It would form one single covalent bond when it bonds to nonmetals.

A nonmetal atom will gain three extra electrons when it bonds to three hydrogen atoms. For the molecule to be stable, that nonmetal atom should be three electrons away from the next noble gas element. Each of the atoms in question should contain 8 - 3 = 5 valence electrons when neutral. Which column on a periodic table contains such elements?

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3 years ago
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Is this equation balanced?<br><br>nh4oh+hc2h3o2=nh4c2h3o2+h2o​
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Answer:

It IS balanced

Explanation:

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A student measures the absorbance of a sample of red dye #3 using a spectrophotometer. If the absorbance is measured as 0.468, w
Gre4nikov [31]

Answer:

5.88 μM is the concentration of red dye in the sample.

Explanation:

Absorbance is defined s capacity of a substance to absorb a light of a specified wavelength.It is calculated by using Beer-Lambert Law:

A=\epsilon lc

A = absorbance

\epsilon = Molar absorptivity

c = concentration

l =  Length of the solution through which light passes

Given, A = 0.468, l = d = 1.00 cm,c = ?

\epsilon =7.96\times 10^4 M^{-1} cm^{-1}

A=\epsilon lc

0.468=7.96\times 10^4 M^{-1} cm^{-1}\times 1.00 cm\times c

c=5.8793\times 10^{-6} mol/L=5.8793 mol/(\mu L)\approx 5.88mol/(\mu L)

(1 L= 1,000,000 \mu L)

5.88 μM is the concentration of red dye in the sample.

5 0
3 years ago
The _____ number is a positive or negative number assigned to an atom according to a set of arbitrary rules.
sergeinik [125]

I think it is oxidation number

5 0
3 years ago
A sample of calcium carbonate weighs 2.1 kilograms (kg). There are 1,000 grams (g) in 1 kg, and 1 Times. 109 nanograms (ng) in 1
TiliK225 [7]

Answer:

2.1 x 10¹²ng

Explanation:

Mass of the calcium carbonate given is:

                    2.1kg  

We need to take this mass to nanogram, ng.

Since :

               1000g  = 1kg

           10⁹g  = 1ng

So;

          1kg  = 1000 x 10⁹ = 10¹²ng

So;

      2.1kg   will give;

                Since

              1kg  gives 10¹²ng

             2.1kg will give 2.1 x 10¹²ng

5 0
3 years ago
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