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Liono4ka [1.6K]
2 years ago
7

Evaluate expression: 3(5g + 5 - 2)

Mathematics
1 answer:
stepladder [879]2 years ago
8 0

Answer: 15g + 9

Step-by-step explanation: Have a brilliant day!- Lily ^_^ Plz mark brainliest.

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The cylinder shown has a volume of π in3. Find the volume of a cone with the same base and height as the cylinder
Luden [163]
The volume would be 1/3π in³.

The volume of a cone is 1/3 the volume of a cylinder with the same radius and height.
7 0
3 years ago
If the altitude is √7, find the volume. 36√7 cu. units 18√7 cu. units 12√7 cu. units
rosijanka [135]

Answer:

Volume = 12\sqrt{7} cubic units

Step-by-step explanation:

Volume of the square pyramid is given as ⅓*area of base*height of pyramid.

Where,

Area of base = 6*6 = 36

Height of pyramid = altitude = \sqrt{7} units

Plug the values into the formula to find volume.

Volume = \frac{1}{3}*36*\sqrt{7}

Volume = 12*\sqrt{7}

Volume = 12\sqrt{7} cubic units

8 0
3 years ago
Keisha solved the following equation: 4x − 2x + 8 = 6(x + 4) Step Work Justification 1 2x + 8 = 6(x + 4) Combine like terms 2 2x
kolbaska11 [484]

4x - 2x + 8 = 6(x + 4)   Given

(4x - 2x) + 8 = 6(x + 4)

2x + 8 = 6(x + 4)     Combine like terms

2x + 8 = (6)(x) + (6)(4)

2x + 8 = 6x + 24    Distributive Property

2x - 6x + 8 = 6x - 6x + 24

-4x + 8 = 24      Subtraction Property of Equality

-4x + 8 - 8 = 24 - 8

-4x = 16    Subtraction Property of Equality

-4x : (-4) = 16 : (-4)

x = -4       Division Property of Equality

4 0
3 years ago
Quadrilateral ABCD has vertices at A(0,0), B(0,2), C(6,2), and D(6,0). Find the vertices of the quadrilateral after a dilation w
valentinak56 [21]

Answer:

A=0

B=0,3

C=9,3

D=9,0

Step-by-step explanation:

Multiplies all the vertices bay scale factor 3/2

5 0
2 years ago
Find the discriminant and determine the nature of the roots to the quadratic equation
Katen [24]
№17
x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2}  \\  \\  x_{1} = \frac{-6+8}{2} =1 \\  \\  x_{2} = \frac{-6-8}{2} =-7
Answer: x₁ = 1
               x₂ = - 7

№18
2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\  \\ D= -3 ^{2} -4*2=9-8=1 \\  \\  x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\  \\  x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5
Answer: x₁ = 1
               x₂ = 0,5.

№19
2 x^{2} -4x-5=0 \\  D=-4 ^{2} -4*2*(-5)=16+40=56 \\  \\  x_{1}= \frac{4+ \sqrt{56} }{2*2}  = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5}  \\  \\  x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} -  \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 

Answer: x₁ = 1 + √3.5
               x₂ = 1 - √3.5

3 0
3 years ago
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