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ololo11 [35]
3 years ago
6

The uniform dresser has a weight of 90 lb and rests on a tile floor for which the coefficient of static friction is 0.25. If the

man pushes on it in the horizontal direction, thetatheta= 0o, determine the smallest magnitude of force F needed to move the dresser. Also, if the man has a weight of 150 lb, determine the smallest coefficient of static friction between his shoes and the floor so that he does not sli
Engineering
1 answer:
Juliette [100K]3 years ago
3 0

Answer:

a) F = 736.065\,lbf, b) \mu_{k} = 0.15

Explanation:

a) The uniform dresser is modelled by using the following equations of equilibrium:

\Sigma F_{x} = F - \mu_{k}\cdot N = 0

\Sigma F_{y} = N-m\cdot g=0

After some algebraic manipulation, the following formula is derived:

F = \mu_{k}\cdot m \cdot g

F = (0.25)\cdot (90\,lbm)\cdot (32.714\,\frac{ft}{s^{2}} )

F = 22.5\,lbf

b) The man is described by the following equations of equilibrium:

\Sigma F_{x} = -F + \mu_{k}\cdot N = 0

\Sigma F_{y} = N-m\cdot g=0

After some algebraic manipulation, the following formula for the static coefficient of friction is:

\mu_{k} = \frac{F}{m\cdot g}

\mu_{k} = \frac{22.5\,lbf}{150\,lbf}

\mu_{k} = 0.15

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Answer:

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Explanation:

#include "hw6.h"

//---------------------------------------------------

// Constructor function

//---------------------------------------------------

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}

//---------------------------------------------------

// Destructor function

//---------------------------------------------------

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{

// Intentionally empty

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//---------------------------------------------------

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//---------------------------------------------------

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for (int c = 0; c < COLS; c++)

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//---------------------------------------------------

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//---------------------------------------------------

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{

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//---------------------------------------------------

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//---------------------------------------------------

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// Check column

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// Check first diagonal

count = 0;

for (int d = 0; d < WIN; d++)

if ((r+d < ROWS) && (c+d < COLS) &&

(board[r+d][c+d] == player)) count++;

if (count == WIN) return true;

 

// Check second diagonal

count = 0;

for (int d = 0; d < WIN; d++)

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//---------------------------------------------------

// Print the Connect4 board

//---------------------------------------------------

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cout << "\n";

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cout << " ";

for (int c = 0; c < COLS; c++)

cout << c << " ";

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//---------------------------------------------------

// Main program to play Connect4 game

//---------------------------------------------------

int main()

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  int choice;

  int counter = 0;

  srand (time(NULL));

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  while (board.MakeMove(choice,'H') == false){

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  counter++;

  }

 

  if (board.CheckWin('C')){

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  board.PrintBoard();

}

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