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Usimov [2.4K]
3 years ago
10

Fill in the blank answers please help.

Chemistry
1 answer:
Archy [21]3 years ago
8 0

Answer:

I took a screen shot hope this helps!!!

https://screenshot.best/A7QIKV.lnk

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What is the ratio of the areas of the signals in the h nmr spectrum of pentan-3-ol?
Damm [24]

The ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

<h3>What is a NMR spectrum?</h3>

Nuclear magnetic resonance spectroscopy is a spectroscopy that shows the detailed structure and chemical environment of a chemical element.

Pentan-3-ol contain 12 hydrogen atoms. In H-NMR spectra, hydrogen atoms have same environment gives a signal.

There are 4 different kinds of signals due of the 4 different environment experienced by these 12 hydrogens.

Thus, the  ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

Learn more about NMR spectrum

brainly.com/question/9812005

#SPJ4

8 0
2 years ago
What is pseudo - order reaction​
zubka84 [21]

Explanation:

The reactions which are not truly of first order but become reactions of first order under certain conditions are called pseudo first order reactions.

For example, hydrolysis of ester

7 0
2 years ago
Read 2 more answers
Label the parts of the atom.<br><br> Which atomic particle determines the identity of the atom?
zavuch27 [327]
A: Electron
B: Neutron
C: Proton
3 0
3 years ago
+ H₂O
trapecia [35]

Answer:

None of these are correct, because there is no way to balance this equation, but I hope these steps help you figure out your answer.

Explanation:

Count out the single amounts of elements you have on both sides of the equation. To be balanced, you need to have the exact same for each element.

Before balanced Left side.

Cl-2

O-8

H-2

Before balanced right side.

H-1

Cl-1

O-3

That means we need to increase Hydrogen, Chlorine and Oxygen on the right for sure and see how that affects the equation. You can keep adding the Coefficients until the # of elements begin to match on each side.  

(I tried to balance this equation, it doesn't work, there is too much on the reactants side for what the product is.)

8 0
3 years ago
If 36.2g of Acetic Acid (HC2H302) was dissolved in 300. mL of water, what is the
uysha [10]

Answer:

2.01 M

Explanation:

Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)

The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.

36.2g \times \frac{1mol}{60.05g} = 0.603mol

Step 2: Convert the volume of solution to liters

We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)

300mL \times \frac{1L}{1000mL} = 0.300L

Step 3: Calculate the molarity of the solution

The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution

M = \frac{0.603mol}{0.300L} = 2.01 M

7 0
3 years ago
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