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wel
2 years ago
15

Define thermal and electrical conductivity, solubility, magnetism, melting and boiling points

Chemistry
1 answer:
Anon25 [30]2 years ago
3 0

Answer:

<u>thermal conductivity:</u> the rate at which heat is transferred by conduction through a unit cross-section area of a material, when a temperature gradient exits perpendicular to the area

<u>electrical conductivity:</u> the measure of the amount of electrical current a material can carry or it's ability to carry a current

<u>solubility:</u> the ability to be dissolved, especially in water

<u>magnetism:</u> a physical phenomenon produced by the motion of electric charge, resulting in attractive and repulsive forces between objects

<u>melting point:</u> the temperature at which a given solid will melt.

<u>boiling point:</u> the temperature at which a liquid boils and turns to vapor

Explanation:

hope this helps :D pls mark brainliest :D

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2Na2SO4 :How many atoms for each element are in the formula?<br><br> S=<br> O=<br> Na=
yuradex [85]

Answer:

S=  2(1)  = 2

O=  2(4)  = 8

Na= 2(2)  = 4

Explanation:

The given compound is:

          2Na₂SO₄  

An element is a distinct substance that cannot be split up into simpler substances.

So;

  Number of atoms of elements here are:

S=  2(1)  = 2

O=  2(4)  = 8

Na= 2(2)  = 4

6 0
3 years ago
A 25 kg rock is placed in a graduated cylinder with water.the volume of the fluid is 18.3ml.calculate the density of the rock in
ipn [44]

Answer:

=> 1366.120 g/mL.

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 25 Kg

Volume (v) = 18.3 mL.

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

First let's convert 25 Kg to g;

1 Kg    = 1000 g

25 Kg = ?

= \frac{25 × 1000}{1}

= 25000 g

Substitute the values into the formula:

p =  \frac{25000 g}{18.3 ml}

= 1366.120 g/mL.

Therefore, the density (rho) of the rock is  1366.120 g/mL.

8 0
2 years ago
By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling
vova2212 [387]

It is found that scuba diver’s can safely ascend up to 52.53 ft without Breathing out.

By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling or exhaling then

p_{1} =patm+pH_{2} O

p_{1} = 101325+ρgh_{1}

It is given that height is 125ft. Put the value of h in above formula:

h1  =125ft=38.1m

ρ=1.04g/mL=1040kg/m^{3}

g=9.81                                  

p_{1} =101325Pa+388711.44

p_{1}   =490036.44‬Pa                

p_{2} =p atm  =101325Pa

It is known that volume and pressure can be expressed as:

V*P=const.

where, V is volume and P is pressure.

Now,              

V_{1} *p_{1} =V_{2}  *p_{2}

V_{2} /V_{1}=p_{2} /p_{1}

V_{2} /V_{1} =490036.44/101325

V_{2} /V_{1}=4.84

Assume constant temperature

d of seawater = 1.04 g/mL; d of Hg = 13.5 g/mL.

now p_{1} =p atm​+pH_{2} O =490036.44Pa

V*p=const                              

where, V is volume and P is pressure.

Now,              

V_{1} *p_{1} =V_{2}  *p_{2}

V_{2} /V_{1}=p_{2} /p_{1}

V_{2} /V_{1} =490036.44/X

p_{2} =490036.44pa/(V2/V1) =326690.96Pa

p_{2} =patm +pH_{2} O

p_{2} =101325Pa+ρgh_{2}

326690.96Pa=101325Pa+ρgh_{2}

ρgh1  =151987.5-101325=225365.96‬‬Pa

ρ=1,04g/mL=1040kg/m3

g=9.81

h_{2} =225365.96/‬ρ∗g

​h_{2}  =225365.96  / ‬1040∗9.81

h_{2}  =22.09m= 72.47ft

ΔH=H_{1} -H_{2}

=125-72.47

=52.53ft

So she can safely ascend up to 52.53 ft without Breathing out

To know more about Scuba diver here

brainly.com/question/15430942

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6 0
1 year ago
To three significant digit,what is the mass percentage of iron in the compound Fe2O3​
svlad2 [7]

69.9%

Explanation:

To find the mass percentage of iron in the compound in Fe₂O₃, we would go ahead to express the given molar mass of the iron to that of the compound.

 Mass percentage  = \frac{molar mass of Fe}{Molar mass of Fe_{2}O_{3}  }  x 100

Molar mass of Fe = 55.85g/mol

Molar mass of O = 16g/mol

Molar mass of Fe₂O₃ = 2(55.85) + 3(16) = 159.7‬g/mol

Mass percentage  = \frac{2(55.85)}{159.7}  x  100   = 69.94% = 69.9%

learn more:

Mass percentage brainly.com/question/8170905

#learnwithBrainly

4 0
3 years ago
A saturated solution of manganese(II) hydroxide was prepared, and an acid–base titration was performed to determine its KspKsp a
trapecia [35]

Answer:

10.945 x 10^-4

Explanation:

Balanced equation:

Mn(OH)2 +  2 HCl  -->  MnCl2  +  H2O

it takes 2 moles HCL for each mole Mn(OH)2

Next find the molarity of the Mn(OH)2 solution

= (1 mole Mn(OH)2 / 2 mole HCl)  X (0.0020 mole HCl / 1000ml) X (4.86 ml)    

= 4.86 x 10^-3 mole  

this is now dissolved in (70 + 4.86)  =  74.86 ml or 0.07486 L

thus [Mn(OH)2]  =  4.86 x 10^-3 mole / 0.07486 L  =  0.064921 M

Ksp =  [Mn2+][OH-]^2  =  4x^3  =  4(0.064921)^3  = 10.945 x 10^-4

6 0
3 years ago
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