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1 year ago

If you break the illustration below into four groups of stars to smiley faces, what would be the ratio?

Mathematics

2 answers:

klio [65]1 year ago

8 0

Answer:

Step-by-step explanation:

there are 3 stars to 1 smiley face

im sorry if I was wrong.

maw [93]1 year ago

3 0

Answer:

Step-by-step explanation:

3 stars for every smile

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A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He gained weight at a rate of 5.55.55

Juli2301 [7.4K]

Answer:

The equation for the relationship between the weight and number of months is $W(t)= 5.5t+79.5$

Step-by-step explanation:

we know that

A linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept (value of y when the value of x is equal to zero)

or say b is the actual weight of the wrestler.

In this problem

m=5.5 kg/month

Let

W ⇒ the sumo wrestler's weight in kg (dependent variable)

t ⇒ the time in months (independent variable)

The linear equation is equal to

$W(t)=5.5t+b$

where

b is the actual weight when he started the diet.

Now Given

W = 140 kg

t = 11 months

substitute in the linear equation to find the value of b

$140 = 5.5\times11 +b\\140 = 60.5+b\\b = 140-60.5\\b = 79.5\ kg$

$W(t)= 5.5t+79.5$

Hence,The equation for the relationship between the weight and number of months is $W(t)= 5.5t+79.5$

7 0

2 years ago

True False Problem Enter T or F depending on whether the statement is true or false. (You must enter T or FTrue and False will n

slamgirl [31]

Answer:

Step-by-step explanation:

5 0

2 years ago

Prove: cot(x) sec^4(x) = cot(x) +2tan(x) + tan^3(x)

masha68 [24]

$\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad\qquad 
sec(\theta)=\cfrac{1}{cos(\theta)}\quad\qquad 1+tan^2(\theta)=sec^2(\theta)\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}
\qquad \qquad cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\\\\
-------------------------------\\\\
cot(x)sec^4(x)=cot(x)+2tan(x)+tan^3(x)\\\\
-------------------------------\\\\$

$\bf \textit{so, let's do the left-hand-side}\\\\
cot(x)sec^2(x)sec^2(x)\implies cot(x)[1+tan^2(x)][1+tan^2(x)]
\\\\\\
cot(x)[1^2+2tan^2(x)+tan^4(x)]
\\\\\\
cot(x)+2tan^2(x)cot(x)+tan^4(x)cot(x)
\\\\\\
cot(x)+2\cdot \cfrac{sin^2(x)}{cos^2(x)}\cdot \cfrac{cos(x)}{sin(x)}+\cfrac{sin^4(x)}{cos^4(x)}\cdot \cfrac{cos(x)}{sin(x)}
\\\\\\
cot(x)+2\cdot \cfrac{sin(x)}{cos(x)}+\cfrac{sin^3(x)}{cos^3(x)}\implies \boxed{cot(x)+2tan(x)+tan^3(x)}$

8 0

2 years ago

From previous polls, it is believed that 66% of likely voters prefer the incumbent. A new poll of 500 likely voters will be cond

Vladimir79 [104]

Answer:

The mean and standard deviation of the number preferring the incumbent is mean = 330, standard deviation = 10.59.

Step-by-step explanation:

We are given that From previous polls, it is believed that 66% of likely voters prefer the incumbent.

A new poll of 500 likely voters will be conducted. In the new poll the proportion favoring the incumbent has not changed.

Let p = probability of voters preferring the incumbent = 66%

n = number of voters polled = 500

<u>So, the mean of the number preferring the incumbent is given by;</u>