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2 years ago

The tires on a mining truck are 14 ft tall. Which measurement is it (diameter, radius, or circumference)

Mathematics

1 answer:

GalinKa [24]2 years ago

4 0

Answer:

this is quite easy. if the tire is 14 ft. tall, that would mean the diameter is 14 ft. as well (do to a tire being round). the radius is half of the diameter, meaning the radius is 7 ft. finally, to find the circumference, you would have to multiply pi by 2 (6.28) then multiply this by the radius to make 43.98 ft.

Step-by-step explanation:

D = 14

R = 14/2 = 7

C = 2(pi) x 7 = 6.28 x 7 = 43.98

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What is the same as 1.5 in a fraction

jeka94

Answer:

the answers is 3 over 2 in fraction form

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2 years ago

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What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C

butalik [34]

ANSWER

$10C_5(2)^{5}( - 3)^5$

EXPLANATION

The given binomial expansion is:

${(2x - 3y)}^{10}$

Compare this to

${(a + b)}^{n}$

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

${x}^{5} {y}^{5}$

This implies that, r=5.

The terms in the expansion can be obtained using

$T_{r+1}=nC_ra^{n-r}b^r$

We substitute the given values to obtain;

$T_{5+1}=10C_5(2x)^{10-5}( - 3y)^5$

$T_{6}=10C_5(2x)^{5}(3y)^5$

$T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5} {y}^{5}$

Hence the coefficient is;

$10C_5(2)^{5}( - 3)^5$

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3 years ago

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A small factory planned to produce a batch of men’s shirts in 8 days. But producing 10 more shirts per day than planned, they fi

a_sh-v [17]

In unit of batches over days, let r be the planned rate and R be the actual increased rate. The difference between R and r is described as 10 shirts per day.

R-r=10

Rate Time Batches

Planned r 8 1

Actual R 7 1

$\left[\begin{array}{c}r=1/8&R=1/7&R-r=HowManyBatchesInTenShirts\end{array}\right]$