I think you can multiply how many are defective in a sample by how much more stuff there is
Answer:
The answer is 85
Step-by-step explanation:
The equation used to find the sum of an arithmetic series is: (n/2) * (a1 + an).
n in this case is 10 (the number of numbers in the series)
an is 22 (plug in 10 to the expression 3n-8)
and a1 is -5 (plug in 1 to the expression 3n-8)
so when you plug everything in to the final equation, you get
(10/2) * (-5 + 22)
5 * 17
85
Factor the following:
x^2 - 16 x + 63
The factors of 63 that sum to -16 are -7 and -9. So, x^2 - 16 x + 63 = (x - 7) (x - 9):
Answer: (x - 7) (x - 9)
Answer:
x = ±
- 3
Explanation:
I'm assuming you want the solutions to that equation, so here goes! (If not, please comment.)
(x-3)(x+9)=27
Let's FOIL this all out and expand. (Remember: First, Outer, Inner, Last.)
x^2 + 9x - 3x - 27
(first+ inner + outer + last)
x^2 + 9x - 3x - 27 = 27
Combine like terms, and add 27 to both sides.
x^2 + 6x - 27 + 27 = 27 + 27
x^2 + 6x = 54
Let's complete the square, because factoring doesn't work, and because it's good practice.
x^2 + 6x + ___ = 54 + ____
In the blank we will put b/2 ^2 = 6/2 ^2 = 3^2 = 9 to complete the square.
x^2 + 6x + 9 = 54 + 9
Now we've got a perfect square factor:
(x + 3)^2 = 63
sqrt(x+3)^2 = 
x + 3 = ± 
x = ±
- 3
We would need the data of their classmates scores to complete this answer