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marin [14]
3 years ago
9

Which of the following objects will have the greatest change in motion? here's the image

Chemistry
2 answers:
never [62]3 years ago
6 0
Answer: D
The large force applied to an object with a small mass will have the greatest change in motion because it would move the most since the object is very light and the force is the largest. Hope that makes sense and helps!!
IrinaK [193]3 years ago
4 0

Answer:

D

Explanation:

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It would be c. Newspaper story
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3 years ago
Read 2 more answers
PLEASE I NEED HELP NOW!!! I WILL GIVE 25 POINTS
padilas [110]
If I did this correctly the balanced equation would be:
14H⁺+Cr₂O₇²⁻+6I⁻→3I₂+2Cr³⁺+7H₂O

oxidation half: (iodide was oxidized)
2I⁻→I₂+2e⁻

reduction half: (chromium was reduced)
14H⁺+Cr₂O₇²⁻+6e⁻→2Cr³⁺+7H₂O

H⁺ comes from the solution.  It is in the final reaction since in redox reactions the oxygen is turned into water since it can't just go away.  I multiplied the oxidation half reaction by 3 in order for both half reactions to half the same number of electrons since equal numbers of electrons need to be lost and gained for the reaction to be balanced.

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8 0
3 years ago
When the reaction A → B + C is studied, a plot 1/[A]t vs. time gives a straight line with a positive slope. What is the order of
zloy xaker [14]

Answer:

Second order

Explanation:

Given that:

When the reaction A → B + C is studied, a plot 1/[A]t vs. time gives a straight line with a positive slope.

From the integration method for the second order of reaction.

Suppose that:

rate = k₂[A]²

∴

\dfrac{1}{A}=\dfrac{1}{A_0}+k_2t

Therefore, a plot of the linear function \dfrac{1}{A} versus t will be linear with a positive slope k₂ and the intercept on the concentration axis will be \dfrac{1}{A_o}

The linear plot for a second order reaction can be seen in theimage attached below.

7 0
4 years ago
A sample of nitrogen gas occupies 1.55 L at
34kurt

Answer:

The new volume after the temperature reduced to -100 °C is 0.894 L

Explanation:

Step 1: Data given

Volume of nitrogen gas = 1.55 L

Temperature = 27.0 °C = 300 K

The temperature reduces to -100 °C = 173 K

The pressure stays constant

Step 2: Calculate the new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume of the gas = 1.55 L

⇒with T1 = the initial temperature = 300 K

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the reduced temperature = 173 K

1.55 L / 300 K = V2 / 173 K

V2 = (1.55L /300K) * 173 K

V2 = 0.894 L

The new volume after the temperature reduced to -100 °C is 0.894 L

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During Photosynthesis , Plants Transforms Light Energy Into Chemical Energy .
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