An ester , propyl methanoate ( HCOOC₃H₇) when reacts with sodium hydroxide( NaOH) forms sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH).
The reaction is as follows:
HCOOC₃H₇+NaOH ⇒HCOONa + C₃H₇OH
So when propyl methanoate is hydrolyzed in water and in NaOH then sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH) forms
Answer: first option is not a termination
∙CH3 + Cl2 → CH3Cl + Cl∙
Explanation:
Since a radical is formed as part of the product it means it's a propagation step and not a termination step, at termination no free radical exist as product
Answer:
Al is oxidized while Ag is reduced.
Explanation:
The complete molecular equation is;
3Ag2S + 2Al --> 6Ag + Al2S3
Oxidation half equation;
2Al ------> 2Al^3+ + 6e
Reduction half equation;
6Ag^+ + 6e -------> 6Ag
Overall redox reaction equation;
2Al + 6Ag^+ ----->2Al^3+ + 6Ag
Hence; Al is oxidized while Ag is reduced.
Answer:
Explanation:
Density is
mass / volume = d
Mass:
840g
Volume:
7 cm x 4 cm x 10 cm = 280 cm^3
840g / 280 cm^3 = 3 g/cm^3
Answer:
Question: A patient is diagnosed with a damage in the thyroid gland.
Which isotope is used to treat the patient?
Option:
A. Copper-64
B. Cobalt-60
C. Carbon-14
D. Iodine-131
Correct answer : D. Iodine-131
Question: Give the definition of isotopes.
Answer : Isotopes is the atoms of elements with the same proton number but different number of neutrons.
