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GuDViN [60]
3 years ago
14

Arrange the objects in order from least to greatest potential energy. Assume that gravity is constant. (Use PE = m × g × h.) Til

es a 15-kilogram stone found at a height of 3 meters10 kilograms of water stored at a height of 9 metersa 1-kilogram ball located 20 meters in the aira box of books weighing 25 kilograms placed on a shelf 2 meters high
Chemistry
2 answers:
Charra [1.4K]3 years ago
4 0

Answer : The order of potential energy from least to greatest is,

(3) < (1) < (4) < (2)

Explanation :

Formula used :

P.E=m\times g\times h

where,

P.E = potential energy

m = mass of an object

g = gravity constant = 9.8m/s^2

h = height

Now we have to calculate the potential energy of following options.

(1) Tiles a 15-kilogram stone found at a height of 3 meters.

P.E=15Kg\times 9.8m/s^2\times 3m=441J

(2) 10 kilograms of water stored at a height of 9 meters.

P.E=10Kg\times 9.8m/s^2\times 9m=882J

(3) 1-kilogram ball located 20 meters.

P.E=1Kg\times 9.8m/s^2\times 20m=196J

(4) In the area box of books weighing 25 kilograms placed on a shelf 2 meters high.

P.E=25Kg\times 9.8m/s^2\times 2m=490J

From this we conclude that, the order of potential energy from least to greatest is,

(3) < (1) < (4) < (2)

HACTEHA [7]3 years ago
3 0

Answer:

The objects in order from least to greatest potential energy:

Ball < Stone < book < Water

Explanation:

Potential energy is an energy of the body due to its position.

P.E=mgh

m = mas of the body

g = Acceleration due to gravity

h = Height at which body is placed

Potential energy of the stone:

m =  15 kg, h = 3 m , g = 9.8 m/s^2

P.E_1=15 kg\times 9.8 m/s^2\times 3 m=441 J

Potential energy of the water:

m =  10 kg, h = 9 m , g = 9.8 m/s^2

P.E_2=10 kg\times 9.8 m/s^2\times 9 m=882 J

Potential energy of the ball :

m =  1 kg, h = 20 m , g = 9.8 m/s^2

P.E_3=1 kg\times 9.8 m/s^2\times 20 m=196 J

Potential energy of the book :

m =  25 kg, h = 2 m , g = 9.8 m/s^2

P.E_4=25 kg\times 9.8 m/s^2\times 2 m=490 J

The potential energies in order from least to greatest :

P.E_3

The objects in order from least to greatest potential energy:

Ball < Stone < book < Water

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Phantasy [73]

The potential of the hydrogen in water gives the pH of the acidity and basicity of the solution. The pH of the solution is 9.06. Thus, option iii is correct.

<h3>What is pH?</h3>

The pH of a substance is given by the subtraction of the pOH from 14 which is the range of the pH scale.

The dissociation reaction for ammonia is given as,

NH₃ (aq) + H₂O (l)  ⇄  NH₄⁺ (aq) + OH⁻ (aq)

Here, the concentration of ammonia is [NH₃] - x, ammonium ion is [NH₄⁺] + x, and hydroxide ion is x.

The molar concentration of ammonia is,

M = (0.12 M × 0.2 L) ÷ 0.45 L = 0.053 M

The molar concentration of ammonium ion is,

M = (0.15 M × 0.25 L) ÷ 0.45 L = 0.083 M

From the base dissociation constant and previous concentration from the reaction, the value of x or hydroxide ion is calculated as,

Kb = [NH₄⁺][OH⁻] ÷ [NH₃]

1.8 × 10⁻⁵ (0.053 - x) - (0.083 + x) × x = 0

x = [OH⁻] = 1.15 x 10⁻⁵

The pH from the hydroxide ion is calculated as,

pOH = - log [OH⁻]

= - log (1.15 x 10⁻⁵)

= 4.94

Further,

pH = 14 - pOH

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= 9.06

Therefore, option iii. 9.06 is the pH of the solution.

Learn more about pH here:

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1 year ago
Given the following reaction and data, A + B → Products
natima [27]

Answer:

a. Rate = k×[A]

b. k = 0.213s⁻¹

Explanation:

a. When you are studying the kinetics of a reaction such as:

A + B → Products.

General rate law must be like:

Rate = k×[A]ᵃ[B]ᵇ

You must make experiments change initial concentrations of A and B trying to find k, a and b parameters.

If you see experiments 1 and 3, concentration of A is doubled and the Rate of the reaction is doubled to. That means a = 1

Rate = k×[A]¹[B]ᵇ

In experiment 1 and to the concentration of B change from 1.50M to 2.50M but rate maintains the same. That is only possible if b = 0. (The kinetics of the reaction is indepent to [B]

Rate = k×[A][B]⁰

<h3>Rate = k×[A]</h3>

b. Replacing with values of experiment 1 (You can do the same with experiment 3 obtaining the same) k is:

Rate = k×[A]

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Nitric acid (HNO3) is a strong acid that is completely ionized in aqueous solutions of concentrations ranging from 1% to 10% (1.
Alborosie

<u>Given:</u>

Concentration of HNO3 = 7.50 M

% dissociation of HNO3 = 33%

<u>To determine:</u>

The Ka of HNO3

<u>Explanation:</u>

Based on the given data

[H+] = [NO3-] = 33%[HNO3] = 0.33*7.50 = 2.48 M

The dissociation equilibrium is-

            HNO3   ↔    H+      +      NO3-

I            7.50               0                 0

C          -2.48          +2.48              +2.48

E            5.02            2.48              2.48

Ka = [H+][NO3-]/HNO3 = (2.48)²/5.02 = 1.23

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