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CaHeK987 [17]
3 years ago
5

I need help with this problem please

Chemistry
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:Li2O

Explanation:  Lithium is an alkali metal in Group 1.  It has a single valence electron that it would be pleased to give up, or share, with another element.  Oxygen is in Group 16, just one removed from the halogens.  It has 6 valence electrons, and wants 2 mosr to complete it's valence shell.  One lithium will contribute 1 electron, so oxh=ygen will keep looking for a second.  If another lithium is available, it will react with that one also, resulting in Li2O.

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Arrange the compounds in order of decreasing magnitude of lattice energy:
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Answer:

The correct answer is CaO > LiBr > KI.

Explanation:

Lattice energy is directly proportional to the charge and is inversely proportional to the size. The compound LiBr comprises Li+ and Br- ions, KI comprises K+ and I- ions, and CaO comprise Ca²⁺ and O²⁻ ions.  

With the increase in the charge, there will be an increase in lattice energy. In the given case, the lattice energy of CaO will be the highest due to the presence of +2 and -2 ions. K⁺ ions are larger than Li⁺ ion, and I⁻ ions are larger than Br⁻ ion.  

The distance between Li⁺ and Br⁻ ions in LiBr is less in comparison to the distance between K⁺ and I⁻ ions in KI. As a consequence, the lattice energy of LiBr is greater than KI. Therefore, CaO exhibits the largest lattice energy, while KI the smallest.  

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Balance the following equation:<br> Sg + F2 --&gt; SF
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Answer:

S+ F2 ⇒ SF

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Explanation:⇆

⇒

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