Answer:
128
Step-by-step explanation:
You can FOIL (First, Outside, Inside, Last)
(3z+1)(4z+2)
First
(3z+1)(4z+2)
3z * 4z
Outside
(3z+1)(4z+2)
3z * 2
6z
Inside
(3z+1)(4z+2)
4z * 1
4z
Last
(3z+1)(4z+2)
2*1
2
Combine all the products of FOIL together
+ 6z + 4z + 2
Combine like terms
+ 10z + 2
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
Step-by-step explanation:
C= 72..............
C3=216
C=216
3
C = 72
Thanks
Answer:
steps below
Step-by-step explanation:
3 = 2/3 m
m = 9/2
by the matrix property of associative: (A+B)+C = A+(B+C)
H = [-2 8 -1]
m x H = 9/2 x [-2 8 1] = [-9 36 -9/2]
