Answer:
condensation - B, melting - C, sublimation - A, freezing - D
Explanation:
condensation : condenstaion is process of change of phase of a substance from gaseous to liquid
evaporation : evaporation is process of change of phase of a substance from liquid to gaseous.
melting : melting is process of change of phase of a substance from solid to liquid.
freezing : freezing is process of change of phase of a substance from liquid to solid.
sublimation : sublimation is process of change of phase of a substance from solid to gaseous.
The equation for each reaction is written according to the relevant as below.
<h3>Equations of chemical reactions</h3>
The reaction between iron and sulfur to form iron (II) sulfide is written as:

The reaction between hydrogen gas and oxygen gas to form water is written as:

The reaction of aluminum oxide to form aluminum and oxygen gas is written as:

Zinc and copper(II) sulfate react to form zinc(II) sulfate and copper as follows:

Potassium hydroxide and hydrogen bromide react to form potassium bromide and water as follows:

More on equations of chemical reactions can be found here: brainly.com/question/6976143
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718.65 degrees is the initial temperature of the zinc metal sample.
Explanation:
Data given:
mass of zinc sample = 2.50 grams
mass of water = 65 grams
initial temperature of water = 20 degrees
final temperature of water = 22.5 degrees
ΔT = change in temperature of water is 2.50 degrees
specific heat capacity of zinc cp= 0.390 J/g°C
initial temperature of zinc sample = ?
cp of water = 4.186 J/g°C
heat absorbed = heat released (no heat loss)
formula used is
q = mcΔT
q water = 65 x 4.286 x 2.5
q water = 696.15 J
q zinc = 2.50 x 0.390 x (22.50- Ti)
equating the two equations
696.15 = - 22.50+ Ti
Ti = 718.65 degrees is the initial temperature of zinc.
40g= 6.002*10^23
20g atomic weight
Answer:
The first case is an SN2 reaction while the second case is an SN1 reaction
Explanation:
In the first case, what we have is an SN2 bimolecular reaction. It should be recalled that sodium ethoxide is a strong nucleophile. Strong nucleophiles lead to SN2 substitution in secondary alkyl halides where SN1 or SN2 mechanisms are probable. The observed mechanism now depends on the actual nucleophile used in the reaction. Since a strong nucleophile is used, 3-ethoxy-1-pentene is obtained as shown in the image attached to this answer.
In the second case, a weaker nucleophile, ethanol is used. The use of a weak nucleophile leads to an SN1 mechanism. The 3-Chloro-1-pentene forms a secondary carbocation as shown in the image attached. This secondary carbocation can re-arrange itself to give the two products; 3-ethoxy-1-pentene and 1-ethoxy-2-pentene as shown in the reaction mechanism in the image attached. The structure of the contributor leading to the formation of 3-ethoxy-1-pentene is clearly shown in the image attached.