All categories

3 years ago

Pls help me out with this question!

Chemistry

1 answer:

Novay_Z [31]3 years ago

8 0

Sodium chloride if it’s not im sorry :)

You might be interested in

Calculate the molarity of a solution prepared by dissolving 6.80 grams of AgNO3 in 2.50 liters of solution.

tester [92]

Answer:

0.016M

Explanation:

First we find the mole of AgNO3 by using the formula mass/molar mass..

Then we find molarity by the formula mole/volume...

I hope you get this..

7 0

3 years ago

1. A gas having the following composition is burnt under a boiler with 50% excess air.

jeka94

The composition of the stack gas are :

$CH_4$ = 0.8713

$C_3H_8$ = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of $CH_4$ : 70% of 100 g = 70 g

Mass of $C_3H_8$ : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of $CH_4$ : $\frac{70 g}{16.04 g/mol}$ = 4.3 mole

Number of moles of $C_3H_8$ : $\frac{15 g}{144.1 g/mol}$ = 0.10 mole

Mass of CO : $\frac{15 g}{28.01 g/mol}$ = 0.53 mole

Now to calculate the mole fraction of each we use the formula:

Mole fraction of $CH_4$ : $\frac{4.3}{4.935}$ = 0.8713

Mole fraction of $C_3H_8$ : $\frac{0.10}{4.935}$ = 0.0202

Mole fraction of CO : $\frac{0.53}{4.935}$ = 0.107

Hence, composition of the stack gas are:

$CH_4$ = 0.8713

$C_3H_8$ = 0.0202

CO = 0.107

Learn more about mole fraction here:

brainly.com/question/13135950

#SPJ1

8 0

3 years ago

What is the result of multiplying

vlabodo [156]

Answer:

i believe it's C

Explanation:

the result of multiplying (2.5 * 1010) and (3.5 x 10-7) is 8.8.10^3

5 0

2 years ago

Is ice silicate or nonsilicate

WINSTONCH [101]

Ice is the solid phase of water, so it is not silicate.

7 0

4 years ago

The distance between the centers of the two oxygen atoms in an oxygen molecule is 1.21 x 10-8 cm. What is this distance in inche

liq [111]

Answer:

The distance between the centers of the two oxygen atoms in an oxygen molecule is $4.76\times 10^{-9}inch$

Explanation:

We know, 1 inch = 2.54 cm

So, $1.21\times 10^{-8}cm=(1.21\times 10^{-8})\times (\frac{1}{2.54})inch$

= $4.76\times 10^{-9}inch$

So the distance between the centers of the two oxygen atoms in an oxygen molecule is $4.76\times 10^{-9}inch$

6 0

3 years ago

Pls￼ help me out with this question!

Pls help me out with this question!