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3 years ago

7

Louis is saving money for a car, he invests $1,200 in an account that pays an interest rate of 7.5%. How many years will it take

for the account to reach $14,000?

1 answer:

Artist 52 [7]3 years ago

3 0

Answer: n + d = 30

0.05n + 0.10d = 2.20

^^ ur system of equations

Step-by-step explanation:

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2+2 how do i add this???????????????

emmasim [6.3K]

Answer:

4

Step-by-step explanation:

You must simply combine the two

6 0

3 years ago

Find the distance between each pair of points whose coordinates are given. Round to the nearest tenth if necessary.

cestrela7 [59]

Answer:

5.8

Step-by-step explanation:

Y e s .

Using the Distance formula and all.

5 0

3 years ago

(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)

klemol [59]

Answer:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

Step-by-step explanation:

Given the expression

$\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)$

Remove parentheses: (a)=a

$=-t^4-5t^3-10t^2+9t^3+3t^2-1$

Group like terms

$=-t^4-5t^3+9t^3-10t^2+3t^2-1$

Add similar elements

$=-t^4-5t^3+9t^3-7t^2-1$ ∵ $-10t^2+3t^2=-7t^2$

Add similar elements

$=-t^4+4t^3-7t^2-1$ ∵ $-5t^3+9t^3=4t^3$

Thus, the equivalent expression in simplified form:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

4 0

3 years ago

Which side lengths form a right triangle?<br> Choose all answers that apply:

kkurt [141]

Answer:

All 3 are right triangles.

Step-by-step explanation:

In a right triangle c^2 = a^2 + b^2 where c is the longest side. ( by Pythagoras).

a) 3^2 = 9, 6^2 = 36 and √27 ^ 2 = 27

36 = 9 + 27

So this is a right triangle.

b)

17^2 = 289, 15^2 = 225 and 8^2 = 64

289 = 225 + 64

Also right triangle.

c) √50 ^ 2 = 50, 5^2 = 25 and 5^2 = 25

So also right triangle.

3 0

2 years ago

Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)

natima [27]

$\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}$

$x^3=x\cdot x^2$ , and $x(x^2+2x+1)=x^3+2x^2+x$ . Subtracting this from the numerator gives a remainder of

$(x^3+10x^2+13x+39)-(x^3+2x^2+x)=8x^2+12x+39$

$8x^2=8\cdot x^2$ , and $8(x^2+2x+1)=8x^2+16x+8$ . Subtracting this from the previous remainder gives a new remainder of

$(8x^2+12x+39)-(8x^2+16x+8)=-4x+31$

$-84x$ is not a multiple of $x^2$ , so we're done. Then

$\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}=x+8+\dfrac{-4x+31}{x^2+2x+1}$

4 0

3 years ago