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3 years ago

Please help. i need help. i will adore u

Mathematics

1 answer:

AlexFokin [52]3 years ago

6 0

AnswerThe first one the rabbit population would go down because the abundance on lynx

the sencond one would be the lynx population would increase because of the abundance of food

Step-by-step explanation:

I hope this helped :)

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Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and t

WINSTONCH [101]

Answer:

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.

How long will it take for this population to grow to a hundred rodents? To a thousand rodents?

Step-by-step explanation:

Use the initial condition when dp/dt = 1, p = 10 to get k;

$\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}$

Seperate the differential equation and solve for the constant C.

$\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2} }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}$

You have 100 rodents when:

$100=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{100} \\\\2t=98\\\\t=49\ months$

You have 1000 rodents when:

$1000=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{1000} \\\\2t=99.8\\\\t=49.9\ months$

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3 years ago

A cake-baking kit says:

olganol [36]

What’s the rest of the qurstion?

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Simplify the expression.<br> -2 + 2/5b - 1/4b +6=

OleMash [197]

Answer:

3b/20+4

Step-by-step explanation:

-2 + 2/5b - 1/4b + 6

Combine 2/5b and 1/4b to get 3/20b

-2 + 3/20b + 6

Add −2 and 6 to get 4.

4+3/20b

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FrozenT [24]

Answer:

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Step-by-step explanation:

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