Answer:
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Explanation:
The formula to be used here is
Q = It
where Q is the quantity of electricity and it is measured coulombs (C); 2.8 × 10⁻⁸ C or 0.000000028 C
I is current and it is measured in ampere (amps or A); unknown
t is time and it is measured in seconds (s); 0.05 s
Since, average current is what is unknown
I =Q/t
I = 0.000000028/0.05
I = 5.6 × 10⁻⁷ A
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Answer:
Explanation:
3.64 x 10⁶ J passes through 6 walls
heat energy passing through 1 wall = 0.606 x 10⁶ J
Surface Area of 1 wall A = .285² = 0.081225 m²
Temperature Difference = T₁ - T₂ = 26.8 + 94.7 = 121.5
Thickness of wall d = 3.75 x 10⁻² m
Rate of heat flow per second R = 
=7.01 J per s.
Formula for rate of heat flow
R = 
Where K is thermal conductivity.
7.01 = 
K = 2.66 X 10⁻² W m⁻¹s⁻¹
Answer:
B
Explanation:
im sure that the last one and the first are correct and the second one is wrong .
KE = 0.5mV^2 = 0.5 * 0.0025 * (20)^2 =
<span>0.5 Joules.</span>
The mass of the first body is double the mass of the second body.
This all revolves around Newtons 2nd law of motion that states F=m*a.
If we understand that body one has the same force applied but half of the acceleration than body two, we can easily understand that it has to do something with the objects mass. This is because mass and acceleration in newtons 2nd law are inversely proportional. This means if and objects force stays the same, but it’s mass doubles, then the acceleration must be half its original value. And if the acceleration doubles and the force stays constant than the mass must have halved from its original value. It sounds quite complicated but it’s very simple. Hopefully this helps!!!
