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madreJ [45]
4 years ago
11

Your question: "the picture shows a professional diver with a mass of 93 kg from a 25 m high cliff. Earths Gravity is acting on

the diver. Which statement best describes the reaction force to earths gravity in this situation?"
Physics
1 answer:
GuDViN [60]4 years ago
6 0

When we see the words "Which statement ... ", we know right away that there
will be a list of choices, and we're expected to select our answer from that list.
Strangely, the list of answer-choices for this question has been lost.

Similarly, when we see the words "The picture shows ... ", it's hard to fight
the impulse to look around.  In the present situation, <em>that's</em> missing too.

If the diver is just standing there, then the reaction force provided by the cliff
against his feet must be exactly equal to his weight.  If the vertical forces acting
on the soles of his feet were not balanced, then his feet would be accelerating
vertically.

His weight is  (mass) x (gravity) =

                     (93 kg) x (9.8 m/s²) = <em>911.4 newtons</em> (about 205 pounds) .

That's also the strength of the upward reaction force provided by the cliff.


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Define a medium and state what type of medium sound energy would travel the fastest in
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What are convex mirrors used in?​
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Answer:

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A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that a
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\Phi_C = B(\pi r^2)

The induced voltage is the change of the magnetic flux across the time, then

\epsilon_{emf,C} = \frac{B(\pi r^2)}{t}

At the same time the magnetic flux through the square coil would be given as,

\Phi_S = B(r^2)

And the induced voltage EMF will be

\epsilon_{emf,s} = \frac{B(r^2)}{t}

Equating both expression we have

\epsilon_{emf,s} = \frac{\epsilon_{emf,C}tr^2}{\pi r^2t}

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7 0
3 years ago
monochromatic light from a distant source is incident on a slit 0.75 mm wide. on screen 2 m away, the distance from the central
hjlf

Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25.

<h3>How to find Wavelength of the light?</h3>

When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.

This is a straightforward situation in which we can apply the

Fraunhofer single slit diffraction equation:

y = mλD/a

Where:

y = Displacement from the center line for minimum intensity =  1.35 mm

λ =  wavelength of the light.

D = distance

a = width of the slit = 0.75

m = order number = 1

Solving for λ

λ = y + a/ mD

Changing the information that the issue has provided:

λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  

=5.0625 *10^-7 = 506.25

so

Wavelength of the light 506.25.

To learn more about Wavelength of the light refer to:

brainly.com/question/15413360

#SPJ4

5 0
1 year ago
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