An object that is thrown straight up falls back to Earth. This is one-dimensional motion. (a) When is its velocity zero? (b) Doe
2 answers:
You might be interested in
we know that center of mass is given as
r = (m₁ + m₂
)/(m₁ + m₂)
taking derivative both side relative to "t"
dr/dt = (m₁ d/dt + m₂ d
/dt)/(m₁ + m₂)
v = (m₁ + m₂
)/(m₁ + m₂)
taking derivative again relative to "t" both side
dv/dt = (m₁ d/dt + m₂ d
/dt)/(m₁ + m₂)
a= (m₁ + m₂
)/(m₁ + m₂)
The acceleration of an object in free fall is
Explanation:
We can solve the problem by using Newton's second law of motion, which states that:
where
F is the net force on an object
m is the mass of the object
a is its acceleration
For the object in this problem, we have:
m = 9.9 kg is its mass
F = 97.02 N is the net force on the object
So, we can rearrange the equation to find its acceleration:
This value is actually known as acceleration of gravity (g), and it is the acceleration that any object in free fall has near the Earth's surface, regardless of its mass.
Learn more about Newton's second law here:
And about free fall:
#LearnwithBrainly