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zmey [24]
3 years ago
5

a weightlifter lifts a 1000 newton barbell above his head from the floor to a height of 2.5 meters. he holds the barbell there f

or 5 seconds. how much work does he do during the 5 second interval?
Physics
1 answer:
solniwko [45]3 years ago
7 0
Work done = Potential Energy  = (mg)h

               mg   =  weight of the ball
 
               = 1000 N * 2.5 m  = 2500 Joules.

The work done during the 5 second is 2500 Joules.       
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A. The potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J. Find by
valina [46]

a. The spring is compressed  by  0.174 m.

b.  The vertical distance the dart travels from its position when the spring is compressed to its highest position is 9.6 m.

c. The horizontal velocity of the dart at that time is  13.74 m/s.

d. The horizontal distance from the equilibrium position at which the dart hits the ground is 19.236 m.

<h3>What is potential energy?</h3>

The energy by virtue of its position is called the potential energy.

a. Given is the potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J.

PE  of spring = 1/2 kx²

Put the values, we get

P.E = 0.940 = 1/2 x 62 x²

x = 0.174 m

Thus, the spring is compressed by 0.174 m.

b. Given is a 0.010 kg dart is fired straight up.

The vertical height is find out by

0.940 J = (0.010 kg) (9.8 m/s²) h

h = 9.6 m

Thus, the vertical distance the dart travels from its position is 9.6 m

c. From the conservation of energy principle, total mechanical energy is conserved.

1/2 mv² =mgh

v = √2gh

Plug the values, we get

v = √2 x 9.8x 9.6

v = 13.74 m/s

Thus, the horizontal velocity is  13.74 m/s.

d.  Time that dart spends in air, t = √2h/g

t = √(2x9.6)/9.81

t = 1.4 s

The horizontal distance from the equilibrium position at which the dart hits the ground.

Horizontal distance = (Velocity on x direction) x time

Horizontal distance = 13.74 m/s x 1.4s

Horizontal distance = 19.236 m

Thus, the horizontal distance is 19.236 m.

Learn more about potential energy.

brainly.com/question/24284560

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7 0
2 years ago
in a lab, resonance tubes are used to determine experimentally the speed of sound. using the data given, evaluate the best appro
jek_recluse [69]

The approximate speed of sound is about 761 mph or 335.28 meters/second.

<h3>What's the approximate speed of sound?</h3>

If we consider the normal atmosphere at sea level, the speed of sound is about 761 mph or 335.28 meters/second. The speed of sound is different in different mediums such as solid and liquid.

So we can conclude that the approximate speed of sound is about 761 mph or 335.28 meters/second.

Learn more about speed here: brainly.com/question/4931057

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3 0
2 years ago
In experimental design: What are<br> the two groups?
sp2606 [1]

Answer:

The correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

Explanation:

A two group is a experimental design two groups are the two different groups of subjects divided by the researcher for comparing the data and result to establish relation in variables.

In normal case, one of the two groups one is a group of subjects who get treatment known as experiment or treatment group while other group is known as control group without treatment.

Thus, the correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

7 0
3 years ago
How is the motion of particles in the medium different than the motion of the wave
Ostrovityanka [42]

Answer:

The particles in a medium only vibrate about their equilibrium positions while the waves that they mediate travel through them, transferring vibration to more distant particles in the medium.

In transverse waves, like the waves on a string, the particles of the medium vibrate perpendicular to the direction of the waves. And in longitudinal waves, like sound waves, the particles vibrate in the direction of the wave's travel. What is important to stress about waves is that they do not transfer matter from one place to another, but only energy. The effect is analogous to that observed in a Newton's cradle: the <em>ball manages to transfer energy to the other end without actually moving there</em>.

5 0
3 years ago
Two particles, one with charge -6.29 × 10^-6 C and one with charge 5.23 × 10^-6 C, are 0.0359 meters apart. What is the magnitud
navik [9.2K]

Answer:

Force, F = −229.72 N

Explanation:

Given that,

First charge particle, q_1=-6.29\times 10^{-6}\ C

Second charged particle, q_2=5.23\times 10^{-6}\ C

Distance between charges, d = 0.0359 m

The electric force between the two charged particles is given by :

F=k\dfrac{q_1q_2}{d^2}

F=9\times 10^9\times \dfrac{-6.29\times 10^{-6}\times 5.23\times 10^{-6}}{(0.0359)^2}

F = −229.72 N

So, the magnitude of force that one particle exerts on the other is 229.72 N. Hence, this is the required solution.

4 0
3 years ago
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