Answer:
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
Explanation:
Given data:
Mass of water = 50 g
Initial temperature= T1 = 20°C
Final temperature= T2 = 10°C
Specific heat of water= c = 4.186 J/g. °C
Amount of heat released = Q= ?
Solution:
Formula:
Q = m. C. ΔT
ΔT = T2 - T1
ΔT = 10°C - 20°C
ΔT = -10°C
Now we will put the values in formula.
Q = m. C. ΔT
Q = 50 g . 4.186 J/g. °C . -10°C
Q = - 2093 J
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
V(C₄H₆O₃) = 5.00 mL.
d(C₄H₆O₃) = 1.08 g/mL.
m(C₄H₆O₃) = V(C₄H₆O₃) · d(C₄H₆O₃).
m(C₄H₆O₃) = 5.00 mL · 1.08 g/mL.
m(C₄H₆O₃) = 5.4 g.
n(C₄H₆O₃) = m(C₄H₆O₃) ÷ M(C₄H₆O₃).
n(C₄H₆O₃) = 5.4 g ÷ 102 g/mol.
n(C₄H₆O₃) = 0.0529 mol.
n(C₇H₆O₃) = 2.08 g ÷ 138.1 g/mol.
n(C₇H₆O₃) = 0.015 mol; limiting reactant.
From chemical reaction: n(C₄H₆O₃) : n(C₉H₈O₄) = 1 : 1.
n(C₉H₈O₄) = 0.015 mol.
m(C₉H₈O₄) = 0.015 mol · 180.16 g/mol.
m(C₉H₈O₄) = 2.71 g; theoretical yield.
percent yield od aspirine = 2.57 g ÷ 2.71 g · 100% = 94.83%.
<span>Aluminum foil is a metal so it has the typycal properties of metals. These are the three most representative properties of metals that aluminum foil exhibit:
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</span><span>1) It is good conductor of electricity: this property is consequence of the metallic bond, which permits that the outermost electrons of each atom can flow through the entire network of atoms conducting the electricity.
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</span><span>2) Is is good conductor of heat: this other property of metals is due to transmission of vibration that is carried out between neighboring atoms.
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3) it is ductile: this property means that the metals can be formed into foils.
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<span>Other properties that can be mentioned are: solid at room temperature and mallealble (can form wires)
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Answer:
titanium selenide
Explanation:
The first element in the compound keeps its name and the second one is changed from selenium to selenide.
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