Consider two gases, A and B, are in a container at room temperature. What effect will the following changes have on the rate of
2 answers:
Explanation:
As it is given that two gases A and B are mixed together and kept in a container with constant volume.
Also, kinetic energy of molecules is directly related to temperature as follows.
K.E =
As kinetic energy is directly proportional to temperature. So, when there will be decrease in temperature then kinetic energy of molecules will also decrease leading to less number of collisions between the molecules.
Hence, there will be decrease in rate of reaction.
Thus, we can conclude that when temperature is decreased at a constant volume then rate of reaction will also decrease.
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Answer:
Rate constant of the reaction is .
Explanation:
A + B + C → D + E
Let the balanced reaction be ;
aA + bB + cC → dD + eE
Expression of rate law of the reaction will be written as:
Rate(R) of the reaction in trail 1 ,when :
...[1]
Rate(R) of the reaction in trail 2 ,when :
...[2]
Rate(R) of the reaction in trail 3 ,when :
...[3]
Rate(R) of the reaction in trail 4 ,when :
...[4]
By [1] ÷ [2], we get value of c ;
c = 1
By [3] ÷ [4], we get value of b ;
b = 0
By [2] ÷ [3], we get value of a ;
a = 2
Rate law of reaction is :
Rate constant of the reaction = k