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raketka [301]
3 years ago
14

Consider two gases, A and B, are in a container at room temperature. What effect will the following changes have on the rate of

the reaction between these gases? The temperature is decreased at a constant volume.
Chemistry
2 answers:
Tatiana [17]3 years ago
8 0

Explanation:

As it is given that two gases A and B are mixed together and kept in a container with constant volume.

Also, kinetic energy of molecules is directly related to temperature as follows.

                K.E = \frac{3}{2}kT

As kinetic energy is directly proportional to temperature. So, when there will be decrease in temperature then kinetic energy of molecules will also decrease leading to less number of collisions between the molecules.

Hence, there will be decrease in rate of reaction.

Thus, we can conclude that when temperature is decreased at a constant volume then rate of reaction will also decrease.

Anna [14]3 years ago
4 0

The effect that the following changes have on the rate of the reaction between the gases A and B in a container when the temperature is decreased at a constant volume will decrease because the molecules of A and B are ineracting very slowly due to the decrease in temperature which results to the decrease in kinetic energy.

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1.

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So, concentration of OH⁻(aq) = [OH⁻(aq)] ⇒ (0.05 × 10) ÷ 25 ⇒ 0.02 M

2.

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[Ca²⁺] = 0.02 ÷ 2 = 0.01 M

3.

K_{sp} = [Ca²⁺(aq)] [OH⁻(aq)]²

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K_{sp} = [0.01 × (0.02)²] = 4×10⁻⁶

4.

If reaction is exothermic which means heat energy will get evolved as a result temperature of the reaction media will get increased during the course of the reaction. If temperature is externally increased, the reaction will go backward to accumulate extra heat energy.

5.

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Answer:

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