I would say your answer is 22.4L
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Answer:
C₁₅H₁₅Co₃
Explanation:
Compound = Carbon+ Hydrogen + Cobalt
Mass of carbon = 1.453 g
Mass of Hydrogen = 0.122 g
Mass of Cobalt = 3 - 1.453 - 0.122 = 1.425 g
Dividing all through b their molar masses
Carbon = 1.453 / 12 = 0.1211
Hydrogen = 0.122 / 1 = 0.122
Cobalt = 1.425 / 58.9 = 0.02419
Divide all through by the smallest number (0.02419)
Carbon = 0.1211 / 0.02419 = 5
Hydrogen = 0.122 / 0.02419 = 5
Cobalt = 0.02419 / 0.02419 = 1
The empirical formular = C5H5Co
(C5H5Co)n = 372
[(12 * 5 ) + (5 * 1 ) + 58.9]n = 372
n = 372 / 123.9 = 3
Chemical formular;
C₁₅H₁₅Co₃
When the supply of air or oxygen is poor
The optimal temperature for an enzyme is the one at which the enzyme is the most active and productive.
At temperatures below the optimum temperature, the enzyme still catalyzes the reactions, but with decreased activity.
Even though the temperature increase increases the activity of the enzymes, temperatures that are greater than the optimum cause damage the enzyme strucutre, causing denaturation and loss of function