Question

Chlorine is the most widely used disinfectant for killing pathogens during water treatment. Determine the kilograms of chlorine used daily at a water treatment plant handling 10,000 cubic meters per day of flow at a chlorine dosage of 10 mg/L. [Hint: Multiply the flow rate by the chlorine dosage and make appropriate conversions.] Ans

Answer 1

Explanation:

The given data is as follows.

    Flow of chlorine (Q) = $10,000 m^{3}/day$

Amount of liter present per day is as follows.

                  $10,000 \times 10^{3} l/day$

It is given that dosage of chlorine will be as follows.

                   10 mg/l = $10 \times 10^{-6}$ kg/l

Therefore, total chlorine requirement is as follows.

          Total chlorine requirement = $(10,000 \times 10^{3}) \times (10 \times 10^{-6})$ kg/day

                                        = 100 kg/day

Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.