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3 years ago

C4H9OH(g)+O2(g)→CO2(g)+?H2O(l) what coefficient should be placed in front of H2O to balance the hydrogen atoms?

Chemistry

1 answer:

slava [35]3 years ago

3 0

Answer:

Explanation:

To balance the hydrogen atoms, we check the number of hydrogen on the left side, this is equal to the 10 hydrogen atoms we have in the alkanol.

Now, on the right hand side, we can see we only have two hydrogen atoms in the water molecule. Now, to make equal the number of hydrogen atoms on both sides, we simply multiply the number of hydrogen there by 5 to make it 10 too

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Determine the molarity of 1.2 mol KCl in 1.1 L of a solution?

victus00 [196]

Answer:

1.1 M

General Formulas and Concepts:

Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define variables

1.2 mol KCL

1.1 L of solution

M = unknown

Step 2: Solve for Molarity

Substitute: M = 1.2 mol/1.1 L
Evaluate: M = 1.09091

Step 3: Check

We are given 2 sig figs. Follow sig fig rules.

1.09091 M ≈ 1.1 M

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3 years ago

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Answer:

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Answer-ΔTf = Kfm

Explan

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3 years ago

What fraction of the gas phase molecules initially present for 1.0 atm in the chamber are present at 1.0×10−10 torr?

vivado [14]

The fraction of gas phase molecules is calculated by the division of final pressure to the initial pressure.

Fraction = $\frac{P_{final}}{P_{initial}}$ (1)

Here, initial pressure = 1.0 atm

final pressure = $1.0\times 10^{-10} torr$

First, convert torr into atm

1 atm = 760 torr

final pressure = $\frac{1.0\times 10^{-10}}{760}$

= $1.316\times 10^{-13}atm$

Now, put the value of initial and final pressure in formula (1)

Fraction = $\frac{1.316\times 10^{-13}atm}{1.0 atm}$

= $1.316\times 10^{-13}$

Thus, fraction of the gas phase molecules = $1.316\times 10^{-13}$ $\simeq 1.3\times 10^{-13}$

7 0

4 years ago