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2 years ago

C4H9OH(g)+O2(g)→CO2(g)+?H2O(l) what coefficient should be placed in front of H2O to balance the hydrogen atoms?

Chemistry

1 answer:

slava [35]2 years ago

3 0

Answer:

Explanation:

To balance the hydrogen atoms, we check the number of hydrogen on the left side, this is equal to the 10 hydrogen atoms we have in the alkanol.

Now, on the right hand side, we can see we only have two hydrogen atoms in the water molecule. Now, to make equal the number of hydrogen atoms on both sides, we simply multiply the number of hydrogen there by 5 to make it 10 too

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What is the Molar Mass

Natasha2012 [34]

The molar mass is the mass of a chemical element or a chemical compound (g) divided by the amount of substance (mol).

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3 years ago

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For each property listed, identify the type of element it describes.

Juliette [100K]

Answer:

1.Very good electrical conductivity : Metals (Decreacing order of conductivity)

Silver > Copper > Gold > aluminium

2. Amphoteric : Metal elements

Beryllium , Aluminium , Zinc ,

3.Gaseous at room temperature: mostly Nobel gases elements and some non - metal elements.

Helium ,neon , argon , krypton , fluorine , Oxygen , nitrogen

4.Solid at room temperature: Mostly Metals (few non-metals, metalloid elements)

Metals (Sodium , potassium , calcium , gold are solid)

Non- metals(Carbon ,Boron )

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Explanation:

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2 years ago

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how many grams of antifreeze would be required per 500 g of water to prevent the water from feezing at a temperature of -39° C

andrezito [222]

Answer:

333.7g of antifreeze

Explanation:

Freezing point depression in a solvent (In this case, water) occurs by the addition of a solute. The law is:

ΔT = Kf × m × i

Where:

ΔT is change in temperature (0°C - -20°C = 20°C)

Kf is freezing point depression constant (1.86°C / m)

m is molality of solution (moles solute / 0.5 kg solvent -500g water-)

i is Van't Hoff factor (1, assuming antifreeze is ethylene glycol -C₂H₄(OH)₂)

Replacing:

20°C = 1.86°C / m × moles solute / 0.5 kg solvent × 1

5.376 = moles solute

As molar mass of ethylene glycol is 62.07g/mol:

5.376 moles × (62.07g / 1mol) = 333.7g of antifreeze.

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Sedbober [7]

Paleolithic Era
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