Answer:
1 5/6
Step-by-step explanation:
Answer:
E is not a subspace of 
Step-by-step explanation:
E is not a subspace of
In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.
Consider
(a,b) = (1,1)
(c,d) = (-1,-1)
It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.
But (a,b) + (c,d) = (1-1, 1-1) = (0,0)
and (0,0) is not in E.
By the way, it can be proved that in any vector space all sub spaces must have the vector zero.
<span>1 and 2. Taneisha can send as few as 0 texts, or n>=0.
3 and 4. Taneisha can send as many as 300 texts in a month, or n<=300.
5. In this case, n>=0 and n<=300.
6. Putting these in compound form to make them one statement gives 0 <= n <= 300.</span>