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3 years ago

A light bulb has 0.25 A of current using a voltage of 120 V. What is the power rating for this bulb?

1 answer:

6 0

We can't tell what RATING is printed on the package of bulbs, but right now, the bulb is dissipating IxE= 30 watts of heat and light.

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an object is moving forward with a constant velocity. which statement about this object must be true?

love history [14]

Answer:

• Its acceleration is zero

Explanation:

from definition of acceleration:

${ \rm{acceleration = \frac{change \: in \: velocity}{time} }} \\ \\ { \rm{acceleration = \frac{ \delta \: (velocity)}{time} }}$

• since velocity is constant, change in velocity is zero

${ \boxed{ \rm{ \delta \: (velocity) = 0}}}$

• therefore:

${ \rm{acceleration = \frac{0}{time} }} \\ \\ { \boxed{ \tt{acceleration = 0 \: m {s}^{ - 2} }}}$

4 0

3 years ago

The Sun radiates energy at a rate of about 4×1026W. Earth is about 150×106km from the Sun.

sergiy2304 [10]

The average intensity received on the Earth's surface is $12.6*10^{10} W/m^{2}$

$Intensity = Rate of energy radiated/4\pi R^{2}$

where R is the distance of the earth from the sun.

$I=4*10^{26}/4\pi *[150*106*10^{3}]^{2}$

$I=0.12597*10^{12}$

$I=12.6*10^{10} W/m^{2}$

What is the meaning of the intensity of sunlight?

Sun intensity refers to the amount of incoming solar energy, or radiation, that reaches the Earth's surface. The angle at which the rays from the sun hit the Earth determines this intensity.

What is the average intensity received on the Earth's surface?

The average intensity received on the Earth's surface is given by:

$I=rate of energy radiated/4\pi R^{2}$

Thus, the average intensity received on the Earth's surface is $12.6*10^{10} W/m^{2}$

To know more about the intensity received from the sun:

brainly.com/question/29579262

#SPJ1

8 0

1 year ago

A sound from a source has an intensity of 270 db when it is 1 m from the source. what is the intensity of the sound when it is 3

Lina20 [59]

Sound intensity is inversely proportional to the square of the distance between the source and the receiver.
That is
I = k/r^2
where
k = constant
r = radius

When r=1, the intensity is I₁ = k/1 = k
When r=3, the intensity I₂ = k/3² = k/9
Therefore
I₂ = I₁ /9

In decibels,
I = 10 log₁₀(I/I₀)
where I₀ = reference intensity

When r=1,
10 log₁₀ (I₁/I₀) = 270

When r =3,
10 log₁₀ (I₂/I₀) = 10 log₁₀ [(I₂/I₁)*(I₁/I₀)]
= 10 log₁₀ [(1/9)*(I₁/I₀)]
= 10 log₁₀(1/9) + 270
= 260.5

Answer: 260.5 dB (nearest tenth)

4 0

3 years ago

Water floats on a liquid called "carbon tetrachloride." The two liquids do not mix. A light ray passing from water into carbon t

Oduvanchick [21]

Answer:

1.26

Explanation:

$index \: of \: refraction \: = \: \ \frac{ \sin(angle \: of \: incidence) }{ \sin(angle \: of \: refraction) }$