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zimovet [89]
3 years ago
12

Energy. (4 points)

Physics
1 answer:
zloy xaker [14]3 years ago
4 0
Answer is choice #3: Mechanical energy
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What type of change occurs when water change from a solid to a iquid?
Oksanka [162]
The type of change is melting
6 0
3 years ago
A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear
Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

f_o = f_s\frac {(v+vs)}{v} and f_o = f_s\frac {(v-vs)}{v} when moving towards observer

With f_o of 76 then taking speed in air as 343 m/s we have

76 = f_s\times\frac {(343-vs)}{343}

f_s=\frac {343\times 76}{343-v_s}

Similarly, with f_o of 65 we have

65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}

Now

f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}

v_s=27.76 m/s

Substituting the above into  any of the first two equations then we obtain

f_s=70.07 Hz

4 0
3 years ago
By how much will the velocity of a vehicle change if it accelerates at 10 m/s/s for a period of 10 seconds​
pishuonlain [190]

Answer:

Explanation:

we know that the time rate of change of velocity is called acceleration mathmetically;

a=Δv/Δt

Δv=a*Δt

a=10 m/s²

t=10 sec

Δv=10*10=100 m/s

7 0
4 years ago
Which of these biomes receives the least amount of rainfall every year?
ASHA 777 [7]

Answer:

Desert

Explanation:

The desert receives the least amount of rainfall yearly.

A desert can be described a barren area of land where little amount of rainfall occurs and, because of this, living conditions are not favourable for plants and animal life. Because there is no vegetation in a desert, the bare surface of the ground are subjected to denudation.

5 0
3 years ago
The beautiful Multnomah Falls in Oregon are approximately 206m high. If the Columbia river is flowing horizontally at 2.90m/s ju
zhenek [66]

Answer:

The overall velocity of the water when it hits the bottom is:

v_f=63.61\ \frac{m}{s}

Explanation:

Use the law of conservation of energy.

Call it instant [1] to the moment when the water is just before reaching the falls.

At this moment its height h is 206 meters and its velocity  horizontally v_i is v_i = 2.90m/s.

At the instant [1] the water has gravitational power energy E_g

E_g = mgh

The water also has kinetic energy Ek.

E_k = 0.5mv_i ^ 2

Then the Total E1 energy is:

E_1 = mgh + 0.5mv_i ^ 2

In the instant [2] the water is within an instant of touching the ground. At this point it only has kinetic energy, since the height h = 0. However at time [2] the water has maximum final velocity v_f

So:

E_2 = 0.5mv_f ^ 2

As the energy is conserved then E_1 = E_2

mgh + 0.5mv_i ^ 2 = 0.5mv_f ^ 2

Now we solve for v_f.

gh + 0.5v_i ^ 2 = 0.5v_f ^ 2\\\\9.8(206) + 0.5(2.90) ^ 2 = 0.5v_f 2\\\\v_f^2 = \frac{9.8(206) + 0.5(2.90) ^ 2}{0.5}\\\\v_f = \sqrt{\frac{9.8(206) + 0.5(2.90) ^ 2}{0.5}}\\\\v_f=63.61\ \frac{m}{s}

7 0
3 years ago
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