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erastovalidia [21]

3 years ago

8

Is it about drive if it's about power? Does the subject in question stay hungry and devour? To put in the work and put in the ho

urs, is to take what's ours?

1 answer:

DochEvi [55]3 years ago

3 0

It depends is it a bones or no bones day?

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What is the bottom number (that the blue arrow is pointing to) equal to

mezya [45]

You have to attach something if your using a picture there is no problems there

4 0

3 years ago

Would a decrease in force cause a decrease in pressure

natta225 [31]

IdkAnswer:

Explanation:

4 0

4 years ago

41. Electric and magnetic forces can both make certain objects move. For example, a positively charged particle will repel anoth

notsponge [240]

Answer:

Place the north pole of a magnet next to the north pole of another magnet.

Explanation:

Looking at the comments, we can see that the options are:

Place the south pole of a magnet next to the north pole of another magnet.

Place the north pole of a magnet next to the north pole of another magnet.

First, we know that a positively charged particle will repel another positively charged particle.

The same thing happens for magnetic forces (usually we define a magnetic flow from the south pole to the north pole, so we can define the south pole as the "positive" and the north pole as the "negative", but this is only notation and do not really matter), a south pole of a magnet will repel another south pole of a magnet (and the same happens for the north poles)

Then the correct option is:

Place the north pole of a magnet next to the north pole of another magnet.

8 0

3 years ago

You’re standing at the highest point on the Moon, 10,786 mm above the level of the Moon’s mean radius. You’ve got a golf club an

Anna71 [15]

Answer:

A) v = 1,675 10³ m / s , B) r₂ = 11,673 10⁶ m

Explanation:

A) This exercise we must use Newton's second law, where the forces of gravity are the Moon

F = m a

acceleration is centripetal

a = v² / r

force is the force of universal attraction

F = G m M / r²

we substitute

G m M / r² = m v² / r

v² = G M / r

distance

r = R_moon + h

r = 1.74 10⁶ +1.0786 10⁴

r = 1,750786 10⁶ m

we calculate

v = √ (6.67 10⁻¹¹ 7.36 10²² / 1.75 10⁶)

v = √ (2,8052 10⁶)

v = 1,675 10³ m / s

B) let's use energy conservation

Starting point. In the mountain

Em₀ = K + U = ½ m v² + G m M / r

Final point. Where the speed is zero

$Em_{f}$ = U = G mM / r₂

Em₀ = Em_{f}

½ m v² + G m M / r = G mM / r₂

1 / r₂ = (½ v₂ + G M / r) / GM

let's calculate

1 / r₂ = (½ (1,675 10³)² + 6.67 10⁻¹¹ 7.36 10²² / 1.75 10⁶) /(6.67 10⁻¹¹ 7.36 10²²)

1 / r₂ = (1,4028 10⁶ + 2,805 10⁶) / 49.12 10¹¹

1 / r₂ = 8.5664 10⁻⁷

r₂ = 11,673 10⁶ m

6 0

3 years ago

A 500 kg crate is lifted by a crane and accelerated upward at 2 m/s/s. What is the tension force in the cable pulling up on the

Likurg_2 [28]

Answer = 1000N
F = ma
M = 500kg
a= 2 m/s/s
Solve for F

6 0

3 years ago