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Nastasia [14]
3 years ago
11

Uranium-236 is _____. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-

bomb
Chemistry
2 answers:
nata0808 [166]3 years ago
8 0
<span>Uranium-236 is intermediate nuclei. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-bomb.

Following is the reaction involved in above process:

</span>^{235}U+ ^{1}n →  ^{236}U→ ^{144}Ba + ^{89}Kr + 3 ^{1}n<span> + 177 MeV
</span>
Here, 
^{235}U = Fission material,
^{1}n = projectile,
^{236}U = intermediate nuclei,
^{144}Ba and ^{89}Kr = Fission product



Shkiper50 [21]3 years ago
8 0
The asnwer in the blank would be intermediate nuclei. Uranium-236 is intermediate nuclei created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-bomb. This is use in radioactivity and  generates the heat in nuclear power reactors, and produces the fissile material for nuclear weapons.
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Which characteristic best explains the difference in melting behavior of covalent substances and ionic substances? Ionic substan
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Covalent substances have weaker intermolecular attractions.

Explanation:

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3 years ago
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What is the mass ratio of aluminum to oxygen in aluminum oxide, Al2O3?
liubo4ka [24]

Answer:

9 : 8

Explanation:

Aluminum oxide has the following formula Al₂O₃.

Next, we shall determine the mass of Al and O₂ in Al₂O₃. This can be obtained as follow:

Mass of Al in Al₂O₃ = 2 × 27 = 54 g

Mass of O₂ in Al₂O₃ = 3 × 16 = 48 g

Finally, we shall determine the mass ratio of Al and O₂. This can be obtained as follow:

Mass of Al = 54 g

Mass of O₂ = 48 g

Mass of Al : Mass of O₂ = 54 : 48

Mass of Al : Mass of O₂ = 54 / 48

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Mass of Al : Mass of O₂ = 9 : 8

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5 0
2 years ago
8. A party-supply store sells a helium-gas
MatroZZZ [7]

Answer:

P₂= 116.7 atm

Explanation:

Here apply the Boyle's law equations that states :at constant temperature the volume of a dry mass of a gas is inversely proportional to its pressure.

This is simplified as;

P₁V₁=P₂V₂ where P is pressure and V is volume

Given that;

P₁=1

V₁=1.81 m³

P₂=?

V₂=1.55*10^-2 m³

Apply the formula

1*1.81 =P₂*1.55*10^-2 m³

1.81/1.55*10^-2  =P₂

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7 0
3 years ago
A container of 56mL is at STP, The pressure is increased to 3.6atm and the volume to 162 mL.
Sindrei [870]

Answer:

T2 = 2843.1   oK. This is a huge temperature.  Check it for errors.

Explanation:

Remark

This is the same question as the other one I've answered. Only the numbers have been altered.

Givens

v1 = 56 mL

P1 = 1 atm

T1 = 273o K

v2 = 162

P2 = 3.6 atm

T2 = ?

Formula

Vi * P1 / T1 = V2 * P2/T2

Solution

Rearrange the formula so T2 is on the left

T2 = V2 P2 * T1 / (V1 * P1)          Now just put the numbers in.

T2 = 162 * 3.6* 273 / (56 *1)

T2  =  159213.6/56

T2 = 2843.1                  

3 0
3 years ago
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