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OlgaM077 [116]
3 years ago
8

Describe the two methods of active transport.

Chemistry
2 answers:
artcher [175]3 years ago
7 0
Cars and bike yesyesyesyesyeyseyeyeyeyey
faltersainse [42]3 years ago
7 0

Answer:

ATP and electro chemical

Explanation:

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Draw the Lewis structure for NF3. What orbitals on N and F overlap to form bonds between these elements
jonny [76]
Is there a picture ????????????
4 0
2 years ago
Which is NOT part of a normal microscope?<br> a.ocular<br> b. nosepiece<br> c.stage<br> d.objective
Evgesh-ka [11]

Answer:

I believe it is a Nose piece

Explanation:

3 0
3 years ago
Read 2 more answers
The pressure inside a compressed gas cylinder is 144 atm at 48°C. What will the pressure inside the cylinder be after it is cool
Andrews [41]
<h3>Answer:</h3>

134 atm

<h3>Explanation:</h3>
  • Based on the pressure law, the pressure of a gas varies directly proportionally to the absolute temperature at a constant volume.
  • Therefore; we are going to use the equation;

\frac{P1}{T1}=\frac{P2}{T2}

In this case;

Initial pressure, P1 = 144 atm

Initial temperature, T1 (48°C) = 321 K

Final temperature, T2 (25°C) = 298 K

We need to find the final pressure,

Therefore;

P2 = (P1/T1)T2

    = (144/321)× 298 K

    = 133.68 atm

   = 134 atm

Therefore, the new pressure will be 134 atm.

5 0
4 years ago
34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
Digiron [165]

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

<em>m is the mass of the solution in g,</em>

<em>S is specific heat of the solution = 4.184J/g°C</em>

<em>ΔT is change in temperature = 11.21°C</em>

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

5 0
3 years ago
What is the mass of 1.71 ✕ 1023 molecules of h2so4?
Anuta_ua [19.1K]
The equation for calculating a mass is as follows:

m=n×M

Molar mass (M) we can determine from Ar that can read in a periodical table, and a number of moles we can calculate from the available date for N:

n(H2SO4)=N/NA

n(H2SO4)= 1.7×10²³ / 6 × 10²³

n(H2SO4)= 0.3 mole

Now we can calculate a mass of H2SO4:

m(H2SO4) = n×M = 0.3 × 98 = 27.8 g



7 0
4 years ago
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