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2 years ago

Describe the two methods of active transport.

Chemistry

2 answers:

artcher [175]2 years ago

7 0

Cars and bike yesyesyesyesyeyseyeyeyeyey

faltersainse [42]2 years ago

7 0

Answer:

ATP and electro chemical

Explanation:

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My labmate discovered a new compound and wanted to try to determine what it could be. We noticed that when mixed with an acid, i

kvv77 [185]

Answer:

it went under the process known as crystalization

Explanation:

am a chemist

4 0

2 years ago

g In the elimination reaction of t-butanol and t-butyl bromide. A. They have a common intermediate and require a strong base B.

11111nata11111 [884]

Answer:

Both reactions share a common intermediate and differ only in the leaving group

Explanation:

The elimination reaction of tertiary alkyl halides usually occur by E1 mechanism. In E1 mechanism, the substrate undergoes ionization leading to the loss of a leaving group and formation of a carbocation.

Loss of a proton from the carbocation completes the reaction mechanism yielding the desired alkene.

In the cases of t-butanol and t-butyl bromide, the mechanism is the same. The both reactions proceed by E1 mechanism. The leaving groups in each case are water and chloride ion respectively.

6 0

2 years ago

Find the number of moles of sodium hydroxide in 25cm3 solution of concentration 0,1 mol/dm3

kozerog [31]

Answer:

0.0025 moles

Explanation:

25cm^3 = 25/1000 dm^3

Conc = mol/dm^3

Mol = conc * dm^3

Mol = 0.1 * 25/1000

3 0

2 years ago

If 45.6 grams of water decompose at 301 Kelvin and 1.24 atmospheres, how many liters of oxygen gas can be produced? Show all of

Artyom0805 [142]

This reaction is called the electrolysis of water. The balanced reaction is:

2H2O = 2H2 + O2

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We are given the amount of water for the electrolysis reaction. This will be the starting point of our calculation.

45.6 grams H2O (1 mol H2O / 18.02 g H2O) (1 mol O2 / 2 mol H2O) = 1.27 mol O2

V = nRT/P = </span><span>1.27 mol O2 (0.08206 atm L / mol K) (301 K) / 1.24 atm
V = 25.20 L O2</span>

6 0

3 years ago

List the number of each type of atom on the left side of the equation 2Na3PO4(aq)+2CoCl2(aq)→2Co3(PO4)2(s)+6NaCl(aq) Enter your

Trava [24]

Answer:

Na(sodium atom) = 6 atoms , P(phosphorus atom) = 2 atoms, Oxygen(Oxygen atom) = 8 atoms , Co(cobalt atom) = 2 atoms, Cl(chlorine atom) = 4 atoms

Explanation:

2Na3PO4(aq) + 2CoCl2(aq) → 2Co3(PO4)2(s) + 6NaCl(aq)

The question ask us to list the number of the kind of atom found on the left side(reactant) of the chemical equation. The question also reiterated that the order of the numbers should be the same as the order of the elements on the left side of the equation.

The type of atoms found on the left side of the equation are as follows;

Na(sodium atom) = 6 atoms

P(phosphorus atom) = 2 atoms

Oxygen(Oxygen atom) = 8 atoms

Co(cobalt atom) = 2 atoms

Cl(chlorine atom) = 4 atoms

The equation on the left hand side have sodium atom, phosphorus atom, oxygen atom, cobalt atom and chlorine atom.

Note: The given equation is not balanced but it can be balanced as follows;

2Na3PO4(aq) + 3CoCl2(aq) → Co3(PO4)2(s) + 6NaCl(aq)

The balanced equation have the following number of atom on the left side:

Na(sodium atom) = 6 atoms

P(phosphorus atom) = 2 atoms

Oxygen(Oxygen atom) = 8 atoms

Co(cobalt atom) = 3 atoms

Cl(chlorine atom) = 6 atoms

5 0

3 years ago