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3 years ago

8

Mass of 4.50 moles of oxygen gas. Answer with 3 significant digits

1 answer:

goldfiish [28.3K]3 years ago

3 0

Answer:

The answer is 144g

Explanation:

This is because oxygen gas (O2) has a mass of 32g and you have 4.5 moles of O2, so you have to multiply 4.5 and 32.

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What are the period and group trends in electronegativities

Leviafan [203]

Electronegativity of an element decreases as we move down a group on the periodic table and electronegativity increases while moving from left to right across a period on the periodic table.

Explanation:

The electronegativity increases as we move from left to right across a period because from left to right across a period, the nuclear charge is increasing Hence the attraction for the valence electrons also increases.
As we move down a group, the atoms of each element have an increasing number of energy levels. The distance between the nucleus and valence electron shell increases and reduces the attraction for valence electrons. Hence electronegativity decreases as we move from top to bottom down a group.

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3 years ago

Calculate the energy required to produce 7.00 mol Cl2O7 on the basis of the following balanced equation. 2Cl2(g) + 7O2(g) + 130

KatRina [158]

Explanation:

As the given chemical reaction equation is as follows.

$2Cl_{2}(g) + 7O_{2}(g) + 130 kcal \rightarrow 2Cl_{2}O_{7}(g)$

Also, it is given that for 2 moles the energy required is 130 kcal. This means that energy required for 1 mole is calculated as follows.

1 mole = $\frac{130 kcal}{2}$

= 65 kcal

Hence, energy required for 7 moles will be calculated as follows.

Energy required = $7 \times 65 kcal$

= 455 kcal

Thus, we can conclude that energy required to produce 7.00 mol $Cl_{2}O_{7}$ on the basis of given reaction is 455 kcal.

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3 years ago

How many molecules are there in 122 grams of NO2

AnnyKZ [126]

Thus, there are 1.47 × 10^(23) molecules present in 122 grams of NO2.

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2 years ago

At a given temperature, the elementary reaction A − ⇀ ↽ − B , in the forward direction, is first order in A with a rate constant

ZanzabumX [31]

Answer:

0.24

Explanation:

We are given that

Rate constant for A= $k=0.0180/s$

Rate constant for B,k'=0.0750/s

We have to find the value of equilibrium constant for the reaction

$A\rightleftharpoons B$

Equilibrium constant, for k= $\frac{k}{k'}$

Using the formula

$k=\frac{0.0180}{0.0750}=0.24$

Hence, the value of the equilibrium constant for the reaction

$A\rightleftharpoons B$ at this temperature=0.24

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3 years ago

N² +H² -> NH³<br> When the equation is balanced, what is the coefficient for hydrogen gas?

Andrej [43]

Answer:

I don't even know I'm sorry

6 0

3 years ago