1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Solnce55 [7]
3 years ago
13

Albert views Henry moving by at a constant velocity. Henry has a light clock and also a stopwatch which were synchronized when a

t rest. As Albert views these two moving clocks, which of these statements would be true according to Albert?
a. The light clock runs slow compared to the stopwatch.
b. The stopwatch runs slow compared to the light clock.
c. The two are still synchronized but run fast.
d. The two are still synchronized but run slow.
Physics
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Answer:

d). The two are still synchronized but run slowly

Explanation:

Here Albert is stationary and Henry is running with a constant velocity  carrying a stopwatch and a light clock which are both synchronized  when they are at rest. Now when both the clock are moving at the same constant speed, then they will remain synchronized and will show the same time. But they will definitely run slow for Albert because Albert is at rest with respect to the two clocks. Observers measures clocks that move relative to them as running slow. This is given by Theory of relativity that when clocks are moving they run slow because everything is relative to each other and it depends on our frame of reference.

You might be interested in
True or False: The only type of satellites in Earth's orbit are natural satellites.
hram777 [196]

False, there are also artificial satellites.

3 0
3 years ago
Read 2 more answers
PLEASE HELP! Explain how energy travels outward from the core and is emitted from the Sun. Include what happens in each layer of
xxMikexx [17]
Fusion occurs in the Sun's core, releasing energy that is transferred outward. Once in the radiative zone, gamma rays are transferred by radiation. They are converted to other types of photons, which move into the convective zone, where they are transferred by convection. Finally, energy is emitted from the photosphere.
8 0
3 years ago
Read 2 more answers
Can you name some people who have shown perseverance?​
Komok [63]

Answer:

Milton Hershey

Steve Jobs

Simon Cowell

Thomas Edison

Explanation:

6 0
4 years ago
If the distance between two objects is increased by a factor of 3 (tripled), how will this affect Fg?
scoray [572]

Answer:

2. F g decreases to 1/9

Explanation:

The formula for calculating the Force of gravity between two masses separated by a distance is expressed as;

F = GMm/d² ... 1

If the distance is tripled, the new force will be;

F1 = GMm/(3d)²

F1 = GMm/9d² ... 2

Divide equation 1 by 2

F/F1 = GMm/d²÷GMm/9d²

F/F1 = GMm/d²×9d²/GMm

F/F1 = 1 * 9

F = 9F1

F1 = 1/9 F

<em>This means that the new force decreases to 1/9</em>

6 0
3 years ago
During a solar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Moon between the Earth and the Sun.
lord [1]

Answer:

(a) F_{sm} = 4.327\times 10^{20}\ N

(b) F_{em} = 1.983\times 10^{20}\ N

(c) F_{se} = 3.521\times 10^{20}\ N

Solution:

As per the question:

Mass of Earth, M_{e} = 5.972\times 10^{24}\ kg

Mass of Moon, M_{m} = 7.34\times 10^{22}\ kg

Mass of Sun, M_{s} = 1.989\times 10^{30}\ kg

Distance between the earth and the moon, R_{em} = 3.84\times 10^{8}\ m

Distance between the earth and the sun, R_{es} = 1.5\times 10^{11}\ m

Distance between the sun and the moon, R_{sm} =  1.5\times 10^{11}\ m

Now,

We know that the gravitational force between two bodies of mass m and m' separated by a distance 'r' is given y:

F_{G} = \frac{Gmm'_{2}}{r^{2}}                             (1)

Now,

(a) The force exerted by the Sun on the Moon is given by eqn (1):

F_{sm} = \frac{GM_{s}M_{m}}{R_{sm}^{2}}

F_{sm} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 7.34\times 10^{22}}{(1.5\times 10^{11})^{2}}

F_{sm} = 4.327\times 10^{20}\ N

(b) The force exerted by the Earth on the Moon is given by eqn (1):

F_{em} = \frac{GM_{s}M_{m}}{R_{em}^{2}}

F_{em} = \frac{6.67\times 10^{- 11}\times 5.972\times 10^{24}\times 7.34\times 10^{22}}{(3.84\times 10^{8})^{2}}

F_{em} = 1.983\times 10^{20}\ N

(c) The force exerted by the Sun on the Earth is given by eqn (1):

F_{se} = \frac{GM_{s}M_{m}}{R_{es}^{2}}

F_{se} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 5.972\times 10^{24}}{((1.5\times 10^{11}))^{2}}

F_{se} = 3.521\times 10^{20}\ N

7 0
3 years ago
Other questions:
  • Susan notices that AC and DF are congruent in the image below. Which step could help her determine if _ABC _ _DEF by SAS?
    10·1 answer
  • What is the face to getting to the next one to 33+33
    5·1 answer
  • If there are 745 watts for every horsepower, how many horses would it take to power a single hundred-watt light bulb?
    6·2 answers
  • Which of the following are examples of levers?
    13·1 answer
  • The diffuser in a jet engine is designed to decrease the kinetic energy of the air entering the engine compressor without any wo
    10·1 answer
  • A motorcycle has a constant acceleration of 3.49 m/s2. Both the velocity and acceleration of the motorcycle point in the same di
    10·1 answer
  • What did classical physics predict would happen to the light given off by an
    14·2 answers
  • A 0.38 kg drinking glass is filled with a hot liquid. The liquid transfers 7032 J of energy to the glass. If the
    12·1 answer
  • Which of the following statements about the force on a charged particle due to a magnetic field are not valid?
    6·1 answer
  • How much time is required for a car engine to do 278 kJ of work, if its maximum power is 95 kW?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!