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Solnce55 [7]
3 years ago
13

Albert views Henry moving by at a constant velocity. Henry has a light clock and also a stopwatch which were synchronized when a

t rest. As Albert views these two moving clocks, which of these statements would be true according to Albert?
a. The light clock runs slow compared to the stopwatch.
b. The stopwatch runs slow compared to the light clock.
c. The two are still synchronized but run fast.
d. The two are still synchronized but run slow.
Physics
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Answer:

d). The two are still synchronized but run slowly

Explanation:

Here Albert is stationary and Henry is running with a constant velocity  carrying a stopwatch and a light clock which are both synchronized  when they are at rest. Now when both the clock are moving at the same constant speed, then they will remain synchronized and will show the same time. But they will definitely run slow for Albert because Albert is at rest with respect to the two clocks. Observers measures clocks that move relative to them as running slow. This is given by Theory of relativity that when clocks are moving they run slow because everything is relative to each other and it depends on our frame of reference.

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Given: Mass of earth Me = 5.98 x 10²⁴ Kg

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            G = 6.67 x 10⁻¹¹ N.m²/Kg²

Required: Smallest possible period T = ?

Formula: F = ma;  F = GMeMsat/r²     Centripetal acceleration ac = V²/r

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equate T from all equation.

F = ma

GMeMsat/r² = Msat4π²/rT²    

GMe = 4π²r³/T²

T² = 4π²r³/GMe  

T² = 39.48(6.37 x 10⁶ m)³/6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)

T² = 1.02 x 10²² m³/3.99 x 10¹⁴ m³/s²

T² = 25,563,909.77 s²

T = 5,056.08 seconds    or around   1.4 Hour

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3 years ago
10. Hamilton How long does it take Lewis travelling at 156 m.p.h to cover 16 miles?
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Answer: Hello!

Lewis is travelling at 165 mph, which means miles per hour, this says that he does 165 miles in one hour.

We want to know how much time takes to cover 16 miles.

this can be calculated as the quotient of the distance and the velocity; this is:

t = \frac{16 mi}{165 mi/h} = 0.096 h

if we want to write this in minutes, then:

we know that one hour has 60 minutes, then 0.096 hours has:

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A certain carbon monoxide molecule consists of a carbon atom mc = 12 u and an oxygen atom mo = 17 u that are separated by a dist
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Answer:

a)  x_{cm} = m₂/ (m₁ + m₂)   d , b)   x_{cm} = 52.97 pm

Explanation:

The expression for the center of mass is

                x_{cm} = 1 / M  ∑ x_{i} m_{i}

Where M is the total masses, mI and xi are the mass and position of each element of the system.

Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon

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Let's reduce the magnitudes to the SI system

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b) let's calculate the value

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            x_{cm} = 52.97 10⁻¹² m

            x_{cm} = 52.97 pm

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