(1) The time of motion of the arrow is 0.25 s.
(2) The vertical height dropped by the arrow as it approaches the target is 0.31 m.
The given parameters:
- <em>Horizontal distance of the arrow, X = 20 m</em>
- <em>Horizontal speed of the arrow, v = 80 m/s</em>
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The time of motion of the arrow is calculated as follows;

The vertical height dropped by the arrow as it approaches the target is calculated as follows;

Learn more about time of motion of projectile here: brainly.com/question/1912408
Work,
in thermodynamics, is the amount of energy that is transferred from one system
to another system without transfer of entropy. It is equal to the external
pressure multiplied by the change in volume of the system. It is expressed as
follows:<span>
W = PdV
Integrating and assuming that P is not affected
by changes in V or it is constant, then we will have:
W = P (V2 - V1)
Substituting the given values:
P = 1.0 atm = 101325 Pa
(V2 - V1) = 0.50 L =
W = 101325 N/m^3 ( 0.50) (1/1000) m^3
W = 50.66 N-m or 50.66 J
<span>
So, in the expansion process about 50.66 J of work is being done.
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Answer:
density
Explanation:
mecurys is significantly smaller and less massive than earth
Answer:
The two value of the wavelength for the out of tune guitar is

Explanation:
From the question we are told that
The wavelength of the note is 
The difference in beat frequency is 
Generally the frequency of the note played by the guitar that is in tune is

Where
is the speed of sound with a constant value 


The difference in beat is mathematically represented as

Where
is the frequency of the sound from the out of tune guitar

substituting values


The wavelength for this frequency is



For the second value of the second frequency



The wavelength for this frequency is


