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Ray Of Light [21]
3 years ago
13

Aray diagram is shown. What does the letter red line represent?

Physics
1 answer:
Fiesta28 [93]3 years ago
4 0

Answer:

Red line is reflected ray.

Explanation:

According to the given figure, the blue line represent the incident ray. It strikes the surface and reflection occurs. The dotted line shows normal.

After reflecting the surface, the ray of light is reflected. Red line shows the reflected light.

In this case, the laws of reflection follows i.e. the angle of incidence is equal to the angle of reflection.

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An arrow is shot at a target 20 m away. The arrow is shot with a horizontal velocity of 80 m/s.
Verdich [7]

(1) The time of motion of the arrow is 0.25 s.

(2) The vertical height dropped by the arrow as it approaches the target is 0.31 m.

The given parameters:

  • <em>Horizontal distance of the arrow, X = 20 m</em>
  • <em>Horizontal speed of the arrow, v = 80 m/s</em>

<em />

The time of motion of the arrow is calculated as follows;

t = \frac{X}{v} \\\\t = \frac{20 }{80} \\\\t  = 0.25 \ s

The vertical height dropped by the arrow as it approaches the target is calculated as follows;

h = v_0_y t + \frac{1}{2} gt^2\\\\h = 0 \ + \ \frac{1}{2} \times 9.8 \times 0.25^2\\\\h =0.31 \ m

Learn more about time of motion of projectile here:  brainly.com/question/1912408

4 0
2 years ago
During a breath, the average human lung expands by about 0.50 l. part a if this expansion occurs against an external pressure of
saveliy_v [14]
Work, in thermodynamics, is the amount of energy that is transferred from one system to another system without transfer of entropy. It is equal to the external pressure multiplied by the change in volume of the system. It is expressed as follows:<span>

W = PdV

Integrating and assuming that P is not affected by changes in V or it is constant, then we will have:

W = P (V2 - V1)

Substituting the given values:
P = 1.0 atm = 101325 Pa
(V2 - V1) = 0.50 L = 
W = 101325 N/m^3 ( 0.50) (1/1000) m^3
W = 50.66 N-m or 50.66 J
<span>
So, in the expansion process about 50.66 J of work is being done.
</span></span><span><span>
</span></span>
8 0
3 years ago
Mercury is similar to Earth's blank ?​
Maurinko [17]

Answer:

density

Explanation:

mecurys is significantly smaller and less massive than earth

7 0
3 years ago
A string of length 3m and total mass of 12g is under a tension of 160N. A transverse harmonic wave with wavelength 25cm and ampl
scoundrel [369]

Answer:

Explanation:wave=wavelength×frequency,

3 0
3 years ago
Two guitarists attempt to play the same note of wavelength 6.50 cm at the same time, but one of the instruments is slightly out
PolarNik [594]

Answer:

The two value of the wavelength for the out of tune guitar is  

\lambda _2 = (6.48,6.52) \ cm

Explanation:

From the question we are told that

     The wavelength of the note is \lambda  =  6.50 \ cm = 0.065 \ m

     The difference in beat frequency is \Delta  f = 17.0 \ Hz

     

Generally the frequency of the note played by the guitar that is in tune is  

        f_1 = \frac{v_s}{\lambda}

Where v_s is the speed of sound with a constant value v_s  =  343 \ m/s

       f_1 = \frac{343}{0.0065}

      f_1 = 5276.9 \ Hz

The difference in beat is mathematically represented as

       \Delta  f =  |f_1 - f_2|

Where f_2 is the frequency of the sound from the out of tune guitar

     f_2 =f_1  \pm \Delta f

substituting values

      f_2 =f_1 + \Delta f

      f_2 = 5276.9 + 17.0  

     f_2 = 5293.9 \ Hz

The wavelength for this frequency is

      \lambda_2 = \frac{343 }{5293.9}

     \lambda_2 = 0.0648 \ m

    \lambda_2 = 6.48 \ cm

For the second value of the second frequency

     f_2 =  f_1 - \Delta f

     f_2 = 5276.9 -17

      f_2 = 5259.9 Hz

The wavelength for this frequency is

   \lambda _2 = \frac{343}{5259.9}

   \lambda _2 = 0.0652 \ m

   \lambda _2 = 6.52 \ cm

8 0
3 years ago
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