Answer:
so the answer is 50%
Step-by-step explanation:The interquartile range is the difference between the upper quartile and the lower quartile. In example 1, the IQR = Q3 – Q1 = 87 - 52 = 35. The IQR is a very useful measurement. It is useful because it is less influenced by extreme values as it limits the range to the middle 50% of the values.
Answer:
20,000m²
Step-by-step explanation:
If they jog 12 km/h for half an hour, they have covered.
12 X 0.5 = 6km in 10 circuits. Making 1 perimeter
6 / 10 =0.6 km (600 m).
To determine area we need to convert this perimeter to length and width. We know that it is a rectangle, with 2 equal widths and 2 equal lengths, and the length is twice the width.
So L = 2W
Perimeter = 2W + 2L
600 m = 2W + 2(2W)
600 m = 6W
W = 100 m
L = 200 m
Area = 100 X 200 = 20,000 m²
Answer: 1/7
Step-by-step explanation: The points create a posotive line so the answer has to be posotive. You then have to look at the rise over run. (0,1) is 1 unit higher than (-7,0) and the run is the ditance between the 2 x exvalues. 7. Rise/run = 1/7
The square root of 25/9 is 5/3
Answer:
Step-by-step explanation:
<u>Given system:</u>
The solution is the common area shaded by the inequalities.
The lines are parallel because of same slope.
Both lines are solid because of equal sign in both inequalities.
The first inequality has a y-intercept of 1 and shaded area is to the left of the line since the value of y is greater as x increases.
The second inequality has a y-intercept of -2 and shaded area is to the right of the line since the value of y is greater as x increases.
The matching graph is the second picture (or attached below) and there is no solution.
