Answer:
18
Step-by-step explanation:
3/1 ÷ 1/6
= 3/ 1 × 6/1
=
3 × 6
1 × 1
= 18
Recall your d = rt, distance = rate * time
now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.
However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.
Answer:
See below for proof.
Step-by-step explanation:
<u>Given</u>:

<u>First derivative</u>

<u />
<u />
<u />

<u>Second derivative</u>
<u />







<u>Proof</u>



![= \left(x+\sqrt{1+x^2}\right)^m\left[m^2-\dfrac{mx}{\sqrt{1+x^2}}+\dfrac{mx}{\sqrt{1+x^2}}-m^2\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%28x%2B%5Csqrt%7B1%2Bx%5E2%7D%5Cright%29%5Em%5Cleft%5Bm%5E2-%5Cdfrac%7Bmx%7D%7B%5Csqrt%7B1%2Bx%5E2%7D%7D%2B%5Cdfrac%7Bmx%7D%7B%5Csqrt%7B1%2Bx%5E2%7D%7D-m%5E2%5Cright%5D)
![= \left(x+\sqrt{1+x^2}\right)^m\left[0]](https://tex.z-dn.net/?f=%3D%20%5Cleft%28x%2B%5Csqrt%7B1%2Bx%5E2%7D%5Cright%29%5Em%5Cleft%5B0%5D)

First of all, you would use the FOIL method for -5(a + 3). This means to just multiply -5 to all of the values in the parenthesis. This would equal:
-5a -15 = -55
Then after, you would add 15 for both sides and get -5a = -40
Divide by -5 on both sides, you get a = 8.
Here is a visual representation: https://puu.sh/zPxLC/a16740d0ce.png
6.25 is the answer to the problem