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stiks02 [169]
3 years ago
6

Of the first 103 elements, how many have just ine letter in their symbol​

Chemistry
1 answer:
malfutka [58]3 years ago
4 0

Answer:

14 elements.

Explanation:

B

boron

C

carbon

F

fluorine

H

hydrogen

I

iodine

N

nitrogen

O

oxygen

P

phosphorus

K

potassium

S

sulfur

W

tungsten

U

uranium

V

vanadium

Y

yttrium

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Which of the following statements best describes why carbon can form a variety of organic compounds? Carbon atoms bond readily w
olga_2 [115]
Answer:
            <span>Carbon readily forms covalent bonds with other carbon atoms.

Explanation:
                   As we know approximately more than 95 % compounds, either isolated, discovered or synthesized belongs to organic compounds containing carbon atoms.
                  This great diversity of organic compounds is due to following facts.

1) Catenation:
                      Carbon has a peculiar behavior of self linkage. This self linkage of one carbon with another is called as catenation. In this way carbon can form a long chain of carbon atom. A branching can also take place when one carbon is bonded further to three of four carbon atoms.

2) Isomerism:
                     Secondly the carbon containing compounds show isomerism. In which molecular formula is same but structural formula is different. For example molecular formula C</span>₅H₁₂ can make following compounds,

                                a)  n-Pentane

                                b)  2-Methylbutane

                                c)  2,2-Dimethylpropane

3) Multiple Bonds:
                            Carbon can form multiple bonds i.e double bond like in alkenes and triple bonds like in alkyne. 

Due to these factors carbon gets very high number of opportunities to form large number of compounds.
7 0
3 years ago
If a system performs 147 kJ of work while receiving 47 kJ of heat, what is change in its internal energy?
Verdich [7]

Answer:

-100 kJ

Explanation:

We can solve this problem by applying the first law of thermodynamics, which states that:

\Delta U = Q-W

where:

\Delta U is the change in internal energy of a system

Q is the heat absorbed/released by the system (it is positive if absorbed by the system, negative if released by the system)

W is the work done by the system (it is positive if done by the system, negative if done on the system)

For the system in this problem we have:

W = +147 kJ is the work done by the system

Q = +47 kJ is the heat absorbed by the system

So , its change in internal energy is:

\Delta U = +47 - (+147) =-100 kJ

6 0
3 years ago
The use of microorganism in our day to day life is.................
Ipatiy [6.2K]

Explanation:

The use of microorganism in our day to day life is making medicine.

7 0
2 years ago
Which statement about the balanced equations for nuclear and chemical changes is correct? (1 point)
iris [78.8K]

The true statement about the balanced equations for nuclear and chemical changes is; both are balanced according to the total mass before and after the change.

A basic law in science is called the law of conservation of mass. Its general statement is that mass can neither be created nor destroyed.

Both in chemical and nuclear changes, mass is involved and in both cases, the law of conservation of mass strictly applies.

This means that for both chemical and nuclear changes; total mass before reaction must be equal to total mass after reaction.

Hence, both reactions are balanced according to the total mass before and after the change.

Learn more: brainly.com/question/22064431

3 0
2 years ago
Read 2 more answers
(C6H6) can be biodegraded by microorganism. if 30 mg of benzene is present, what amount of oxygen required for biodegradation, n
quester [9]

Answer:

36.92 mg of oxygen required for bio-degradation.

Explanation:

5C_6H_6+15O_2\rightarrow 12CO_2+15H_2O

Mass of benzene = 30 mg = 0.03 g (1000 mg = 1 g )

Moles benzene =\frac{0.03 g}{78 g/mol}=0.0003846 mol

According to reaction 5 moles of benzene reacts with 15 moles of oxygen gas.

Then 0.0003846 mol of benzene will react with:

\frac{15}{5}\times 0.0003846 mol=0.0011538 mol of oxygen gas

Mass of 0.0011538 moles of oxygen gas:

0.0011538 mol × 32 g/mol = 0.03692 g = 36.92 mg

36.92 mg of oxygen required for bio-degradation.

4 0
3 years ago
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